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bixtya [17]
1 year ago
8

Dagogo uploads 333 videos on his channel every month. each video averages 151515 minutes in length and gets an average of 150{,}

000150,000150, comma, 000 new views. the average ratio of likes-to-views of dagogo's videos is 1:51:51, colon, 5. dagogo wants to reach a total of 9{,}000{,}0009,000,0009, comma, 000, comma, 000 views on his channel. assuming these rates continue, for how many months does dagogo need to upload videos to get to 9{,}000{,}0009,000,0009, comma, 000, comma, 000 views on his channel?
Mathematics
1 answer:
Luden [163]1 year ago
4 0

To acquire 90000000 views on his channel, he has to upload 20 videos every month.

<h3>According to the given information:</h3>

Every month, he  posts 3 videos to his  channel. An average number of people watch each video. = 1500000

In search of:

How many months must pass before he begins to receive 90,000,000 views on his channel?

Step 1

On his channel, he posts three videos each month.

The average number of views per video is.

3 Videos Receive Views

= 3 * 1500000

= 4,500,000 Views

Number of 4,500,000 views each month

Complete 90000000 Views

Step 2

Total Views/Months = Total Views/Total Views

Days in a month = 90000000/4500000

                             = 20

20 Monthly months in the number

To acquire 90000000 views on his channel, he has to upload 20 videos every month.

20  Months is the right response, so.

To know more about Average number's visit:

brainly.com/question/16956746

#SPJ4

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Please fix the question and help me do it the right way
Anestetic [448]

the last step is wrong because we multiply the powers in this case we do not subtract them.

we use power subtract in division.

we use power multiplication when we raise to power and the root is power like square root of x

\sqrt{x}  =  {x}^{ \frac{1}{2} }

so

\sqrt[3]{x}  =  {x}^{ \frac{1}{3} }

in our case

this step is wrong

2x \times  \sqrt[3]{ \frac{2}{y}  \times  \frac{y}{y} }

it should be

2 x \times  \sqrt[3]{ \frac{2}{y}  \times  \frac{ {y}^{2} }{ {y}^{2} } }

so we get

2x \times  \sqrt[3]{2 {y}^{2} \times  \frac{1}{ {y}^{3} }  }

=  \frac{2x}{y}  \times  \sqrt[3]{2 {y}^{2} }

3 0
2 years ago
Help pls and thank youuuu to whoever helps me !!!!!!
Umnica [9.8K]

Answer:

the first one

Step-by-step explanation:

Not to sure if it's right but hope it helps u ;)

8 0
2 years ago
PLEASE HELP ME ANSWER THESE !!!
Evgen [1.6K]

Answer:

1)9 2)18 3)9. 4)4. 5)carpeting

Step-by-step explanation:

1) divide 63 by 7 = 9

2)multiply 54 by 2 = 108 total weight of the boxes then divide 108 by 6 to get 18

3) 75 -30 to get remaining amount which is 45 then divide by 5 to get how much he will pay each month which is 9

4 24- 12= 12 the remaining for the 3 and divide by 3 to get 4

5) multiply 6 * 9 which is $54 which is cheaper than the $81

5 0
2 years ago
Serena has attached a 10 inch ribbon to the corners of a frame to hang it on the wall. The frame 9 inches wide. How far above th
kherson [118]

Answer: The hook would be 2.2 inches (approximately) above the top of the frame

Step-by-step explanation: Please refer to the picture attached for further details.

The top of the picture frame has been given as 9 inches and a 10 inch ribbon has been attached in order to hang it on a wall. The ribbon at the point of being hung up would be divided into 5 inches on either side (as shown in the picture). The line from the tip/hook down to the frame would divide the length of the frame into two equal lengths, that is 4.5 inches on either side of the hook. This would effectively give us two similar right angled triangles with sides 5 inches, 4.5 inches and a third side yet unknown. That third side is the distance from the hook to the top of the frame. The distance is calculated by using the Pythagoras theorem which states as follows;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (longest side) and AB and BC are the other two sides

5^2 = 4.5^2 + BC^2

25 = 20.25 + BC^2

Subtract 20.25 from both sides of the equation

4.75 = BC^2

Add the square root sign to both sides of the equation

2.1794 = BC

Rounded up to the nearest tenth, the distance from the hook to the top of the frame will be 2.2 inches

4 0
3 years ago
How to write 15,409 in expanded form
Y_Kistochka [10]
15x1000+4x100+9x1
I belive that is edpanded notation.
3 0
3 years ago
Read 2 more answers
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