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damaskus [11]
3 years ago
13

Heres is an problem please answer

Mathematics
2 answers:
vlabodo [156]3 years ago
4 0

Answer:

2

Step-by-step explanation:

Since you are adding a negative, you can subtract by a positive.

flip the question around to get 2 \frac{3}{4} - \frac{3}{4}

the 3/4 would cancel out and you would be left with two

ehidna [41]3 years ago
3 0

Answer:

2

Step-by-step explanation:

the - means you have to subtract to add. so subtract 3 over 4 and you get 2

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80 divided by (16 divided by 2/5 + 3.75
Katarina [22]

Answer:

1.8285714

Step-by-step explanation:

7 0
3 years ago
Which number would fit in?
almond37 [142]

Answer:

Answer is 3/6th

Step-by-step explanation:

Because 2/4 is a half so what is 3 as a half of a fraction which is

3/6

5 0
2 years ago
Read 2 more answers
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
Adele has 6 sheets of stickers .Bea has 9 sheets of the same stickers.how many stickers do they have altogether?
Jlenok [28]
They have 15 sheets of stickers all together
7 0
3 years ago
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Reduce 24/33 to lowest terms
Paha777 [63]

24/33

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is the correct answer

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