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3 years ago

Bonus question ! If you answer something dumb I'll report you .

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

4 0

Hello,
We know that
1/Angle 1= Angle 6= Angle 9= Angle 14=Angle 3= Angle 8= Angle 11= Angle 16

2/Angle 2= Angle 5= Angle 10= Angle 13= Angle 4=Angle 7=Angle 12= Angle 15

Check:
Option A:
Angle 2= Angle 7
Parallel
Option B:
Angle 3= Angle 11
Parallel

Option C:
Angle 1= Angle 12
None

Option D:
Angle 13= Angle 12
Parallel

Option E:
Angle 6 angle 7 are supplementary; supplementary means that both angles add up together to get 180°. To help you understand clearly, you see that when the two angle on the same line like angle 5 and 6, angle 1 and 5. However, for this one it will be False because both angle are obtuse which more than 90°. Hope it help!

irinina [24]3 years ago

4 0

Answer:

Option E:

Angle 6 angle 7 are supplementary; supplementary means that both angles add up together to get 180°. To help you understand clearly, you see that when the two angle on the same line like angle 5 and 6, angle 1 and 5. However, for this one it will be False because both angle are obtuse which more than 90°. Hope it help

Step-by-step explanation:

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What is 6/15-9/15 i need help plz

Xelga [282]

Answer:

-3/15 is the difference between 6/15-9/15

3 0

2 years ago

What is the answer to this expression when x=5 3x+15=?

Nikitich [7]

3(5)+15= 30
because BIDMAS so we would multiply 3 by 5 then add the answer which would be 15 to 15 and we would get 30.

5 0

3 years ago

Read 2 more answers

1. The height of a triangle is 6 m more than its base. The area of the triangle is 56 m². What is the length of the base? Enter

Elodia [21]

Answers:
1. 8 m
2. 17 m
3. 7 cm
4. 2 s

Explanations:

1. Let x = length of the base
x + 6 = height of the base

Then, the area of the triangle is given by

(Area) = (1/2)(base)(height)
56 = (1/2)(x)(x + 6)
56 = (1/2)(x²  + 6x)

Using the symmetric property of equations, we can interchange both sides of equations so that

(1/2)(x²  + 6x) = 56

Multiplying both sides by 2, we have

x² + 6x = 112

The right side should be 0. So, by subtracting both sides by 112, we have

x² + 6x - 112 = 112 - 112
x² + 6x - 112 = 0

By factoring, x² + 6x - 112 = (x - 8)(x + 14). So, the previous equation becomes

(x - 8)(x +14) = 0

So, either

x - 8 = 0 or x + 14 = 0

Thus, x = 8 or x = -14. However, since x represents the length of the base and the length is always positive, it cannot be negative. Hence, x = 8. Therefore, the length of the base is 8 cm.

2. Let x = length of increase in both length and width of the rectangular garden

Then,

14 + x = length of the new rectangular garden
12 + x = width of the new rectangular garden

So,

(Area of the new garden) = (length of the new garden)(width of the new garden)

255 = (14 + x)(12 + x) (1)

Note that

(14 + x)(12 + x) = (x + 14)(x + 12)
= x(x + 14) + 12(x + 14)
= x² + 14x + 12x + 168
= x² + 26x + 168

So, the equation (1) becomes

255 = x² + 26x + 168

By symmetric property of equations, we can interchange the side of the previous equation so that

x² + 26x + 168 = 255

To make the right side becomes 0, we subtract both sides by 255:

x² + 26x + 168 - 255 = 255 - 255
x² + 26x - 87 = 0

To solve the preceding equation, we use the quadratic formula.

First, we let

a = numerical coefficient of x² = 1

Note: if the numerical coefficient is hidden, it is automatically = 1.

b = numerical coefficient of x = 26
c = constant term = - 87

Then, using the quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} = \frac{-26 \pm \sqrt{26^2 - 4(1)(-87)} }{2(1)} 
\newline x = \frac{-26 \pm \sqrt{1,024} }{2}
\newline
\newline x = \frac{-26 \pm 32 }{2}$

So,

$x = \frac{-26 + 32 }{2} \text{ or } x = \frac{-26 - 32 }{2}
\newline x = \frac{6 }{2} \text{ or } x = \frac{-58 }{2}
\newline \boxed{ x = 3 \text{ or } x = -29}$

Since x represents the amount of increase, x should be positive.

Hence x = 3.

Therefore, the length of the new garden is given by

14 + x = 14 + 3 = 17 m.

3. The area of the shaded region is given by

(Area of shaded region) = π(outer radius)² - π(inner radius)²
= π(2x)² - π6²
= π(4x² - 36)

Since the area of the shaded region is 160π square centimeters,

π(4x² - 36) = 160π

Dividing both sides by π, we have

4x² - 36 = 160

Note that this equation involves only x² and constants. In these types of equation we get rid of the constant term so that one side of the equation involves only x² so that we can solve the equation by getting the square root of both sides of the equation.

Adding both sides of the equation by 36, we have

4x² - 36 + 36 = 160 + 36
4x² = 196

Then, we divide both sides by 4 so that

x² = 49

Taking the square root of both sides, we have

$x = \pm 7$

Note: If we take the square root of both sides, we need to add the plus minus sign $(\pm)$ because equations involving x² always have 2 solutions.

So, x = 7 or x = -7.

But, x cannot be -7 because 2x represents the length of the outer radius and so x should be positive.

Hence x = 7 cm

4. At time t, h(t) represents the height of the object when it hits the ground. When the object hits the ground, its height is 0. So,

h(t) = 0 (1)

Moreover, since $v_0 = 27$ and $h_0 = 10$ ,

h(t) = -16t² + 27t + 10 (2)

Since the right side of the equations (1) and (2) are both equal to h(t), we can have

-16t² + 27t + 10 = 0

To solve this equation, we'll use the quadratic formula.

Note: If the right side of a quadratic equation is hard to factor into binomials, it is practical to solve the equation by quadratic formula.

First, we let

a = numerical coefficient of t² = -16
b = numerical coefficient of t = 27
c = constant term = 10

Then, using the quadratic formula

$t = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a} = \frac{-27 \pm \sqrt{27^2 - 4(-16)(10)} }{2(-16)} \newline t = \frac{-27 \pm \sqrt{1,369} }{-32} \newline \newline t = \frac{-27 \pm 37 }{32}$

So,

$t = \frac{-27 + 37 }{-32} \text{ or } t = \frac{-27 - 37 }{-32} \newline t = \frac{-10}{32} \text{ or } t = \frac{-64 }{-32} \newline \boxed{ t = -0.3125 \text{ or } t = 2}$

Since t represents the amount of time, t should be positive.

Hence t = 2. Therefore, it takes 2 seconds for the object to hit the ground.

3 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP

Nikitich [7]

10 x 10 x 10 = $10^{3}$

4 0

3 years ago

Read 2 more answers

Which expression is equivalent to 200? O2./10 1012 10./20 1002

solong [7]

Hey there!

We know options. B and D aren't going to be your answer because they are way too big to be equivalent to 200

In order for you to find out which one is equivalent to 200 you have to calculate you late the options until you get to 200 and then you could do process of elimination!

It can't be A because 2/10 = 0.20 aka 20%

It can't be option. C because 10/20 = 0.50 aka 50%

So none of the above would be your answer

The correct answer would most likely be: 10√2

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

8 0

2 years ago