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enyata [817]
3 years ago
15

I NEED HELPPP ITS DUE AT 6

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

Its c

Step-by-step explanation:

deff fn [24]3 years ago
3 0

Answer:

Your answer is C.) 1/3x - 5

Step-by-step explanation:

Combine like terms!

Add -3 and -2 and you get -5

2/3x - 1/3x = 1/3x

Hope this helps you! :)

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Last year the depth of the river was 4.2 feet deep. This year it dropped 25%. Find the depth of the river this year to cross it.
Novosadov [1.4K]

Answer:

The river is 3.15 feet deep.

Step-by-step explanation:

First let's recognize what we need to find: the depth of the river

We know last year the river was 4.2 feet deep, but it dropped 25%. This means we also need to find how much it dropped. To find this, we need to know what 25% of 4.2 is. Write an equation for this.

y = 25% of 4.2

y = 0.25 • 4.2

y = 1.05

This means that the river dropped 1.05 feet. To know its depth now, we need to subtract 1.05 from 4.2. Write an equation for this.

d = 4.2 - 1.05

d = 3.15

The river is 3.15 feet deep.

Hope this helps!

4 0
3 years ago
If cos θ = .62 and if 0<θ<90 what is the approximate value of sin θ to the nearest hundredth
Deffense [45]
\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \  0\to\boxed{\sin\Theta\approx0.78}
5 0
3 years ago
Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the
Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

\text{Distance}=\text{Speed}\times\text{Time}

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

\Rightarrow6x+18+6x = 162

\Rightarrow12x=162-18

\Rightarrow x=\frac{144}{12}\rightarrow x=12

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be x+3=12+3=15 \text{ mph}

8 0
2 years ago
What division equation is related to 4*6=24
kvv77 [185]
Maybe something like 24/4=6. so sorry if I'm incorrect.
8 0
3 years ago
Read 2 more answers
Leila received a $90 gift card for a coffee store. She used it in buying some coffee that cost $8.64 per pound. After buying the
klasskru [66]
She bought 5 pounds of coffee
3 0
3 years ago
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