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Pie
2 years ago
14

Renaldo has a spinner with 10 equal sectors with labels from 1 to 10. He spins the spinner once. What is the probability that he

gets a number that is a multiple of 3, or a 5?​
Mathematics
1 answer:
Mazyrski [523]2 years ago
4 0

Answer:

2/5

Step-by-step explanation:

3, 6, 9, 5 is four options

4/10 = 2/5

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Which choice provides the most relevant detail?
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1 year ago
2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

  • i.e S(a) = S(b)

75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

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6 0
1 year ago
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Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
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<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

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If CD bisects AB, then:

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The above equation is not true, because:

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Hence, CD does not bisect AB

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