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Ray Of Light [21]
3 years ago
10

The mass of a bag of potatoes is 860 kg round to the nearest 10kg. i) Give the upper and lower bounds for the mass.

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

  • Lower bound ⇒ 855 kg
  • Upper bound ⇒ 865 kg

Step-by-step explanation:

The upper bound is the highest number that a figure can be to be rounded off to the rounded figure.

The lower bound is the lowest number that a figure can be to be rounded odd to the rounded figure.

The lower bound of 860 to the nearest 10 is;

= 855 kg

855 is the lowest figure that can be rounded up to 860.

The Upper bound is;

= 865

865 is the highest figure because no figure above this can be rounded to 860.

<em>855 kg ≤ 860 kg < 865 kg</em>

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Georgia [21]

Answer:

True

Step-by-step explanation:

the parent function f(x) = 1/x has a vertical asymptote at x = 0 and a horizontal asymptote at y = 0

4 0
3 years ago
-9=k-6
Shkiper50 [21]

Answer:

k = -3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-9 = k - 6

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Add 6 to both sides:                    -3 = k
  2. Rewrite:                                         k = -3
3 0
3 years ago
Rewrite the expression in the form 5^n<br><br> (5^-8) (5^-10)
oee [108]

Answer:

Step-by-step explanation:

This problem is all about bases and exponents.  Because we have a quotient and the bases are both 5's, that means that we can use the rule of exponents for quotients to rewrite and simplify:

That's the simplification as long as you are "allowed" to leave the exponent as a negative number.

4 0
3 years ago
Read 2 more answers
If the average of nine consecutive integers is zero, what is the largest integer?
Orlov [11]

Answer:

4

Step-by-step explanation:

The average of the consecutive integers is 0, so the middle number must be 0, with 4 numbers less than 0 and 4 numbers greater than 0.

-4, -3, -2, -1, 0, 1, 2, 3, 4

So the largest integer is 4.

4 0
2 years ago
How to slove for x?​
Luba_88 [7]
Ok so you can see 2 triangles that i highlighted, flip it so it is the same direction as you can see from the drawing
using the similar triangle equation
you get
136/64 = x/136
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hope it help

8 0
3 years ago
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