3 years ago

Bro pls help em bro pls help me bro

Mathematics

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

Step-by-step explanation:

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3 years ago

PLEASE HELP!!! I WILL GIVE BRAINY!!!

11111nata11111 [884]

The first one is 4/3

We can solve by,

${x}^{2} \times 180 = 320$

$x = \frac{4}{3}$

${ \frac{4}{3} }^{2} \times 180 = 320 = true$

~~

The second one is 35.

Idk how to explain...

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The third one is a 6 - gon therefore cannot be C or D.

I'd say the third one is A., it looks like it's caving in.

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3 years ago

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Answer:

P( sum is prime )= 73/216

Step-by-step explanation:

The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.

P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.

The final probability will be sum of the above given probabilities.

Hence P( sum is prime )= 73/216

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