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Volgvan
3 years ago
12

Can anyone help me solve this.I need proper equation..Thanks​

Mathematics
2 answers:
nikklg [1K]3 years ago
8 0

Answer: ?=9

                √2

Step-by-step explanation:

x=9 =a side of squre

y=diagonal

use equation :

y=a√2

y=9√2

y=12.69

artcher [175]3 years ago
3 0

Answer:

y = 9\sqrt{2}

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} }

sin45° = \frac{opposite}{hypotenuse} = \frac{9}{y}

Multiply both sides by y

y × sin45° = 9, that is

y × \frac{1}{\sqrt{2} } = 9

Multiply both sides by \sqrt{2}

y = 9\sqrt{2}

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A 9-meter piece of wire costs $8.64. What is the unit price?
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Step-by-step explanation:

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3 years ago
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
2 years ago
What is the slope of a line that is perpendicular to the line y=-1/3x-6
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Answer:

3

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2 years ago
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