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2 years ago

I am so confused. not sure how to solve need step by step instruction to help please

Mathematics

1 answer:

sladkih [1.3K]2 years ago

7 0

Answer:

Step-by-step explanation:

Since -5 is less than zero, we use the second equation, and substitute the -5 in for the x.

-2(-5)+3=13

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Translate this statement into an equation.

yanalaym [24]

Answer:

1/2x = 3*(27-12)

Step-by-step explanation:

Let x be the number

Is means equals

Difference means subtract

1/2x = 3*(27-12)

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2 years ago

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Out of 60 people surveyed at the movies, 45 people said they bought popcorn.If there were 420 people at the movies how many woul

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Answer:

315

Step-by-step explanation:

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3 years ago

Justus samples 3 oranges from each of his trees ,plus an extra 50 oranges from the whole orchard , to judge whether it is time t

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let there are x number of trees

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2 years ago

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Zigmanuir [339]

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7 0

3 years ago

Determine if triangle ABC with coordinates A (0, 2), B (2, 5), and C (−1, 7) is an isosceles triangle. Use evidence to support y

kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

A (0, 2), B (2, 5), and C (−1, 7)

we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

$d=\sqrt{(5-2)^{2}+(2-0)^{2}}$

$d=\sqrt{(3)^{2}+(2)^{2}}$

$dAB=\sqrt{13}\ units$

step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

$dAC=\sqrt{26}\ units$

step 4

Compare the length sides

$dAB=\sqrt{13}\ units$

$dBC=\sqrt{13}\ units$

$dAC=\sqrt{26}\ units$

$dAB=dBC$

therefore

Is an isosceles triangle

Applying the Pythagoras Theorem

$(AC)^{2} =(AB)^{2}+(BC)^{2}$

substitute

$(\sqrt{26})^{2} =(\sqrt{13})^{2}+(\sqrt{13})^{2}$

$26=13+13$

$26=26$ -----> is true

therefore

Is an isosceles right triangle

8 0

3 years ago