Which set of ordered pairs (x, y) could represent a linear function?

Mathematics

1 answer:

boyakko [2]3 years ago

7 0

Answer = C

because all are not in set pairs only no. C is pair of set

You might be interested in

In the figure shown, FG is tangent to circle D.

romanna [79]

Answer:

Option B

Step-by-step explanation:

From the figure attached,

Circle D is drawn with the radius = DG or DE

A tangent FG has been drawn at a point G on the circle from an external point F.

By theorem,

Radius of a circle is always perpendicular to the tangent, drawn to the circle from an external point.

Therefore, DG ⊥ FG.

Option B will be the correct option.

8 0

3 years ago

How To work this out ?

MrMuchimi

(a) Using the completing the square method, we need to write into the form of where , so
Expand to find the value of c
Notice that we get back the first two terms, the and the .We need to get rid of the last term of '9' as the term was not in the original form. The final form will look like
Hence,
(b)
(c) , square root both sides plus and minus of 2 Hence

6 0

3 years ago

Find an equivalent ratio in simplest terms: 25:75

Sati [7]

Answer:

1:3

Step-by-step explanation:

Both numbers are divisible by 25:

25 ÷ 25 = 1
75 ÷ 25 = 3

∴ The simplified ratio is 1:3

Hope this helps!

5 0

2 years ago

A cylinder has a 12-inch diameter and is 15 inches tall. It is filled to the top with water. A 6-inch-diameter ball is placed wi

Tems11 [23]

The volume of the cylinder is the space occupied by the cylinder. The volume of the water in the cylinder is 1583.36266 in³.

<h3>What is the volume of a cylinder?</h3>

The volume of the cylinder is the space occupied by the cylinder. It is calculated with the help of the formula,

$\text{Volume of the cyllinder}= \pi r^2h$

As it is given that the diameter of the cylinder is 12 inches while the height of the cylinder is 15 inches, also, it has a ball of the diameter of 6 inches placed inside the cylinder, therefore, the volume of the water that is inside the cylinder is the difference in the volume of the cylinder and the volume of the spherical ball.

$\text{Volume of the cyllinder}= \pi r^2h = \dfrac{\pi}{4}d^2 h$