Answer:
I came to the answer of 6.
since ΔCDW similar to ΔUVW, then
UW/CW = UV/CD
UW = CW•UV/CD
CU+CW = CW•UV/CD
CU = CW•UV/CD - CW
= 26•132/24 - 26
= 143 - 26
= 117
The general solution, y(t), which solves the problem by the method of integrating factors is; y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)
<h3>How to solve differential equations?</h3>
We want to find the general solution of;
5t(dy/dt) + y = t⁴
We will divide through by 5t to get;
(dy/dt) + y/5t = t³/6
Using Integration factor, we have;
u(t) = e^∫(¹/₅t) dt = t^(¹/₅)
Thus, we now have;
[t^(¹/₅)](dy/dt) + [t^(¹/₅)]y/5t = [t^(¹/₅)]t³/6
Completing this with a differential calculator gives us the general solution as;
y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)
Read more about differential equations at; brainly.com/question/17201048
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if they are just sitting its not likely but if they are standing especally if they like have there head out of the window yes and the speed if the wind would most likely tear you apart
2.4080 meters.
Remember that the definition of work is force over distance. And that the gravitational potential energy that the turtle has will exactly match the work performed in lifting it. So have the following variables
Mass = 860.24 kg
Work = 20320.7 J = 20320.7 kg*m^2/s^2
Gravitational acceleration = 9.81 m/s^2
And we wish to get an answer in meters. So we need to multiply and divide the three numbers we have with all their related units and derive an answer with the unit of m. We can cancel out most of the units by dividing the work by the gravitational acceleration, so
20320.7 kg*m^2/s^2 / 9.81 m/s^2 = <span>
<span>2071.427 kg*m
Now we can cancel out the kg unit by dividing by the mass of the turtle. So
</span></span><span>
2071.427 kg*m / 860.24 kg = </span><span>
<span>2.407964 m
Rounding to 5 significant figures gives 2.4080 meters.
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