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stealth61 [152]
3 years ago
12

For a population with m = 60, which of the following values for the population standard deviation would cause X = 68 to have the

most extreme position in the distribution?A. s=4B. s=3C. s=2D. s=1
Mathematics
1 answer:
trapecia [35]3 years ago
8 0

Answer:

Option D) s = 1

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 69

X = 68

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Computing z-scores for different standard deviation:

z_1 = \displaystyle\frac{68-60}{4} = 2\\\\z_2 = \displaystyle\frac{68-60}{3} = 2.667\\\\z_3= \displaystyle\frac{68-60}{2} = 4\\\\z_4 = \displaystyle\frac{68-60}{1} = 8

The standard deviation with highest z-score gives the most extreme position in the distribution.

Thus, the most extreme position of X = 68 in the distribution is given by a standard deviation of 1.

Option D) s = 1

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What is the sum of the sequence 152,138,124, ... if there are 24 terms?
N76 [4]

Answer: -216

Step-by-step explanation:

To solve the exercise you must use the formula shown below:

Sn=\frac{(a_1+a_n)n}{2}

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a_1=152\\a_n=a_{24}

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Read 2 more answers
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