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AysviL [449]
2 years ago
15

Find an equation in slope-intercept form for the line containing the following points.

Mathematics
1 answer:
mr_godi [17]2 years ago
3 0

Answer:

y=-x-2

Step-by-step explanation:

slope-intercept form is y = mx+b

slope is change in y over change in x, which is -5-(-3)/(3-1) = -1

y = -x+b

plugging in a point, like (1,-3), we have -3 = -1+b. b = -3+1 = -2

y = -x-2

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Licemer1 [7]

The slope of all parallel lines are equal.

The slope of a line in the form y=mx+c is m.

1. The given equation is: y=4x+2.  The slope of this line is m=4. The slope of the line parallel to this line is also 4.

2. The given equation is y=\frac{2}{7}x+1. The slope of this line is m=\frac{2}{7}.

The slope of the line parallel to it is also \frac{2}{7}.

3. The next equation is y+9x=13. The slope intercept form is y=-9x+13.

The slope of this is m=-13. The line parallel to it also has slope which is -13.

4. The given equation is y=-\frac{1}{2}x+4. The slope of this line and the line parallel to it is m=-\frac{1}{2}

5. The equation is 6x+2y=4. We simplify to get: 3x+y=2.

The slope-intercept form is y=-3x+2. The line parallel to this line has slope m=-3

6. Assuming the line is y=-3x+9, then the slope is m=-3

7. Assuming the line is -5x+5y=4, then the slope-intercept form is y=x+\frac{4}{5} and the slope of the line parallel to this line is m=1

8. The equation is 9x-5y=4. The slope intercept form is y=\frac{5}{9}x-\frac{4}{9}. The slope of the line parallel to this line is m=\frac{5}{9}

9. The given equation is -x+3y=6. The slope intercept form is y=\frac{1}{3}x+2. The line  parallel to this line also has slopem=\frac{1}{3}.

10.  Assuming the given line is 6x-7y=10, then y=\frac{6}{7}x-\frac{10}{7} and the line parallel to it has slope m=\frac{6}{7}

11. Assuming the line is y-x=-3, then y=x-3 and the slope of the line parallel to it is m=1

12. The given line is 3x-5y=6. This implies that y=\frac{3}{5}x-\frac{6}{5}

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what arc i mean where is the image

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