The simplest form of the given algebraic expression √(250c³/9d⁶) is; 5c * (√10c)]/3d³
<h3>How to simplify algebra problems?</h3>
We are given the algebra problems as;
√(250c³/9d⁶)
Now 250c³ can be broken down into 250 = 25c² × 10c
Thus, we now have;
√(250c³/9d⁶) = [√(25c²) * (√10c)]/√9d⁶
When we breakdown the above expression, we have;
5c * (√10c)]/3d³
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Answer:
Andre has more money than Bob. If Andre gave Bob $20, they would have the same amount. While if Bob gave Andre $22, Andre would then have twice as much as Bob. How much does each one actually have?
Step-by-step explanation:
Here is the first sentence:
"If Andre gave Bob $20, they would have the same amount."
Algebraically:
1) x − 20 = y + 20.
(Andre -- x -- has the same amount as Bob, after he gives him $20.)
Here is the second sentence:
"While if Bob gave Andre $22, Andre would then have twice as much
as Bob."
Algebraically:
2) x + 22 = 2(y − 22).
(Andre has twice as much as Bob -- after Bob gives him $22.)
To solve any system of two equations, we must reduce it to one equation in one of the unknowns. In this example, we can solve equation 1) for x --
x − 20 = y + 20
implies x = y + 40
-- and substitute it into equation 2):
y + 40 + 22 = 2(y − 22).
That is,
y + 62 = 2y − 44,
y − 2y = − 44 − 62,
according to the techniques of Lesson 9,
−y = −106
y = 106.
Bob has $106. Therefore, according to the exression for x, Andre has
106 + 40 = $146.
I hope this helps u! :D
Answer:
<h2>2/3-1/2= 1/6 and that is your answer </h2>
by the use of elimination method
make all coefficients of subject to be eliminated similar..by multiplying the coefficients with one another
for eqn(i)
5(-10y+9x=-9)
-50y+45x=-45
for eqn(ii)
9(10y+5x=-5)
90y+45x=-45
-50y+45x=-45
90y+45x=-45
...subtract each set from the other...
we get
-140y+0=0
y=0
from eqn(i)
10y+5x=-5
0+5x=-5
x= -1
