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omeli [17]
3 years ago
6

Gerry arrived at the bus stop x hours past noon. Dale arrived 4 hours later. Pat arrived at 5 P.M., x hours after Dale.

Mathematics
1 answer:
victus00 [196]3 years ago
8 0

Answer:

<em>Gerry arrived at the bus station at 12:30 P.M.</em>

Step-by-step explanation:

From noon and 5:00 P.M. there are 5 hours.

Gerry, Dale, and Pat arrived at the bus stop within that interval, which means the sum of the times elapsed between their arrival times must be 5.

4 out of the 5 hours elapsed since Gerry and Dale's arrivals. This means there is only one hour left for twice x.

If twice x is one hour, then x is half an hour. Thus, the complete sequence of arrivals is:

Gerry arrived at the bus station at 12:30 P.M.

Dale arrived at the bus station at 4:30 P.M.

Pat arrived at the bus station at 5:00 P.M.

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Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w
aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0
3 years ago
Is x = -12 a solution of x^2 +10x+25=49?
Tresset [83]

Answer:

Yes

Step-by-step explanation:

{x}^{2}  + 10x + 25 = 49 \\  {x}^{2}  + 10x + 25 - 49 = 0 \\  {x}^{2}  + 10x - 24 = 0 \\ (x + 12)(x -2 ) = 0 \\  \\ x  + 12 = 0 \\ x =  - 12 \\  \\  \\ x  - 2 = 0 \\x = 2

I hope I helped you^_^

8 0
2 years ago
HELP PLEASE :(
Softa [21]

Answer: The customer should buy Giana’s jewelry box.

Step-by-step explanation:

The jewelry boxes are rectangular prisms, in order to find the box that would hold the most amount of jewelry we need to find the volumes of each box.

V= l.w.h

Katherine’s box: 5x5x5= 125

Giana’s box: 10x12x2= 240

Jackson’s box: 10x5x4= 200

3 0
3 years ago
2x² + 166 +30
Darya [45]

Answer:

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5 0
3 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
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