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Anton [14]
3 years ago
14

Ned help please ASAP!!!!!

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0
The answer would be a (not too sure) but it makes a little bit sense
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How do you solve quadratic equations?
masha68 [24]
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-B (+or-) sqrt of b^2 - 4 x A x C
________________________  divide it by
               2 x A
                                                   There is usually an original equation that looks like:  Ax^2 + Bx + C = 0    Use the variables from the equation to the left to fill the upper equation.  (You can also look up a better formula if confused).

8 0
3 years ago
How do you rewrite this problem in slope-intercept form
Sergio039 [100]

Solution

-6x - 3y = 9              Add 6x to both sides

-6x + 6x - 3y = 9 + 6x

-3y = 9 + 6x             Or more conventionally

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y = 6x/-3 + 9/-3

y = - 2x - 3  

5 0
3 years ago
PLEASE HELP ASAP I have no idea how to solve this pls pls pls
xz_007 [3.2K]

Answer:

Step-by-step explanation:

you have to use trigonometric functions

cos 30 = adj. /hyp.

cos 30 = 12 / y

y = 12/cos 30 ≅13.86

tan 30 = opp./adj

tan30 = x / 12

x = 12 tan30 ≅6.93

5 0
3 years ago
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