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kondaur [170]
3 years ago
6

During the past month, you withdrew $22 from your savings account and then deposited $24. If your balance at the end of the mont

h is $120, how much did you have in your account at the beginning of the month?
Mathematics
1 answer:
TEA [102]3 years ago
3 0

Answer:

I believe the answer would be 118; the reason for that would be you would take $120 then take $22 and add it to the amount because withdrew means you are taking money out so how ever much money you took out would be the amount that you had in your saving. Then if you are depositing $20 you would subtract that amount of money because deposit means that you are adding that money to what you add so  you would then subtract that to get the original amount.

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Firdavs [7]

Answer:

14-3x=26

Step-by-step explanation:

When it says "is" and then a number, that means that it is the answer. In this case, 26.

Product means multiplying.

8 0
3 years ago
The Graph describes the water level of creek after a rainstorm which best describes the domain in context?
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The domain of a function are its possible input values

The domain of the function is <em>(b) all real numbers greater than or equal to 0.</em>

From the graph, we have the following observations

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Read more about domain at:

brainly.com/question/2709928

5 0
2 years ago
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1. Given

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3 0
3 years ago
Option 1:<br><br> Find x. Show all work.
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Using law of cosines:

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Rewrite to get:

X = 12/cos(22)

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Round the answer as needed.

5 0
2 years ago
Read 2 more answers
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Advocard [28]
Check the picture below.

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\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
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