For the case of a line through
(
2
,
7
)
and
(
1
,
−
4
)
we have
slope
m
=
Δ
y
Δ
x
=
−
4
−
7
1
−
2
=
−
11
−
1
=
11
Using the point
(
2
,
7
)
we can write the equation of the line in point slope form as:
y
−
7
=
m
(
x
−
2
)
where the slope
m
=
11
.
That is:
y
−
7
=
11
(
x
−
2
)
To get point intercept form, first expand the right hand side so...
y
−
7
=
11
x
−
(
11
⋅
2
)
=
11
x
−
22
Then add
7
to both sides to get:
y
=
11
x
−
15
=
11
x
+
(
−
15
)
This is point intercept (
y
=
m
x
+
c
) form with slope
m
=
11
and intercept
c
=
−
15
.
Answer: hopes this helps i spent a lot of time on it !!!:)lol
2
0
+
3
6
−
8
−
1
2
2
0
+
1
0
1
0
ℎ
−
1
5
−
1
2
−
1
4
5
6
−
6
3
8
−
1
8
−
8
+
1
2
Step-by-step explanation:
Answer:
X-8
Im not 100% sure but i think that is the answe
