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lilavasa [31]
3 years ago
14

Use the diagram of circle C to answer the question.

Mathematics
1 answer:
miskamm [114]3 years ago
4 0

Answer:

V and T are points of tangency to circle C

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9<br> Find the values of r and y.<br> с<br> A<br> 95°<br> B<br> 4x<br> ro<br> D<br> E
Inga [223]

Answer:

  • x = 18°, y = 167°

Step-by-step explanation:

<u>In right triangle sum of two angles is 90°</u>

  • 4x + x = 90°
  • 5x = 90°
  • x = 90°/5
  • x = 18°

<u>Angle y is exterior angle and equals non-adjacent interior angles</u>

  • y = 4x + 95° =
  • 4*18° + 95° =
  • 72° + 95° =
  • 167°
4 0
2 years ago
Grasshoppers are distributed at random in a large field according to a Poisson process with parameter a 5 2 per square yard. How
HACTEHA [7]

In this question, the Poisson distribution is used.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Parameter of 5.2 per square yard:

This means that \mu = 5.2r, in which r is the radius.

How large should the radius R of a circular sampling region be taken so that the probability of finding at least one in the region equals 0.99?

We want:

P(X \geq 1) = 1 - P(X = 0) = 0.99

Thus:

P(X = 0) = 1 - 0.99 = 0.01

We have that:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5.2r}*(5.2r)^{0}}{(0)!} = e^{-5.2r}

Then

e^{-5.2r} = 0.01

\ln{e^{-5.2r}} = \ln{0.01}

-5.2r = \ln{0.01}

r = -\frac{\ln{0.01}}{5.2}

r = 0.89

Thus, the radius should be of at least 0.89.

Another example of a Poisson distribution is found at brainly.com/question/24098004

3 0
3 years ago
Which expression is equivalent to 4x+3x+4-2x
kvv77 [185]

Answer:

5x+ 4

Step-by-step explanation:

First, put all of the x variables together. So 3x+4x=7x

7x + 4 -2x  Since the 2x is negative you can subtract it from 7x and get 5x.

you can not add the four to the 5x because it does not have a matching variable.

So, you have: 5x+ 4

6 0
3 years ago
Answer please it’s a big exam
melomori [17]

Answer:

Solve for be is 56

Step-by-step explanation:

That the answer

4 0
3 years ago
Read 2 more answers
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
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