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denis-greek [22]
2 years ago
9

Plz help this is due today i would have done it myself but i totally forgot about these so PLZ HELP AND NO LINKS AND NO GROSS PI

CTURES OR I REPORT

Mathematics
2 answers:
Drupady [299]2 years ago
3 0

Answer:

b)

Step-by-step explanation:

lol ;)

Svet_ta [14]2 years ago
3 0

Answer:

a i hoped i helped

Step-by-step explanation:

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if 368 teenagers in a population of 4,310 report that they have smoked at least one cigarette during the past year, to one decim
allochka39001 [22]
Divide the amount of teenagers that smoked by the total population:

368 \div 4310 = 0.0853

Multiply this decimal by 100 to convert into a percentage:

0.0853 \times 100 = 8.53

To round to the nearest decimal place, look at the hundredths value:

8.53
3 > 5
8.53 -> 8.5

8.5% of teenagers reported that they smoked at least one cigarette.
4 0
2 years ago
1 point
swat32

Answer:

\log_{10}(147) = 2.1673

Step-by-step explanation:

Given

\log_{10} 3 = 0.4771

\log_{10} 5 = 0.6990

\log_{10} 7= 0.8451

\log_{10} 11 = 1.0414

Required

Evaluate \log_{10}(147)

Expand

\log_{10}(147) = \log_{10}(49 * 3)

Further expand

\log_{10}(147) = \log_{10}(7 * 7 * 3)

Apply product rule of logarithm

\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)

Substitute values for log(7) and log(3)

\log_{10}(147) = 0.8451 + 0.8451 + 0.4771

\log_{10}(147) = 2.1673

3 0
2 years ago
For Each Data Set, Determine the median, the first and third Quartiles, and the interquartile Range.
inysia [295]
Text per day: median= 26 1st quartile= 19 3rd quartile=38 Interquartile=19 Daily attendance: median=357.5 1st quartile=298 3rd quartile=422 Interquartile= 124
4 0
3 years ago
I need help ASAP. I tried but I didn’t get it
ludmilkaskok [199]

Answer:

the answer is 77.77777(repeating)

Step-by-step explanation:

77 and 7/10 approximately

8 0
3 years ago
Solve 2x2 − 6x = −8.
White raven [17]
2x²-6x+8=0
x²-3x+4=0
D=b²-4ac=9-16=-7
x=(3+/-i√7)/2
correct answer is the last one
3 0
3 years ago
Read 2 more answers
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