Answer:
It is not impossible to answer the question, my apologies for “discrediting” the answer it would have to be Venus, the outer planet most similar to earth.
Explanation:
Venus is very similar to earth, as many studies, research, factual intellectual based concepts - the size, shape, surface gravity, average density, mass, average days of 24 hours, season changes similar to earth, and tilted axis. As well as similar climate make Venus the most accurate answer.
Hope this helps! Thank you for your time.
Normal force, weight, Kinetic friction, and air resistance are a few I think of the top of my head.
I hope this helps
Explanation:
The runner was 8.6km away from the finish line when the bird starts flying.
Therefore it takes the bird 8.6/14.4 = 0.60 hours for the bird to fly to the finish line.
In that 0.60 hours, the runner would have ran an extra 3.6km/h * 0.6h = 2.16km.
Now, the runner and the bird are flying towards each other. The distance between them is 8.6 - 2.16 = 6.44km and their combined speed is 18.0km.
Hence, they will meet in 6.44/18.0 = 0.36 hours.
Overall, the bird flew for 0.60 + 0.36 = 0.96 hours, and flew 14.4km/h * 0.96h = 13.8km.
First convert from mi/h to ft/s. There are 5280 ft to 1 mi, and 3600 s to 1 h, so
36 mi/h = (36 mi/h) * (5280 ft/mi) * (1/3600 h/s) = 52.8 ft/s
Let <em>a</em> be the acceleration of the car. The car's speed at time <em>t</em> is
<em>v</em> = 52.8 ft/s + <em>a</em> <em>t</em>
so that after 5.4 s, it attains a speed of
<em>v</em> = 52.8 ft/s + (5.4 s) <em>a</em>
Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> is the car's initial velocity and ∆<em>x</em> is the distance it's traveled.
We have
(52.8 ft/s + (5.4 s) <em>a</em>)² - (52.8 ft/s)² = 2 <em>a</em> (595 ft)
Omitting units, this equation reduces to
(52.8 + 5.4 <em>a</em>)² - 52.8² = 1190 <em>a</em>
==> 29.16 <em>a</em>² - 619.76 <em>a</em> = 0
==> 29.16 <em>a</em> - 619.76 = 0
==> 29.16 <em>a</em> = 619.76
==> <em>a</em> ≈ 21.25 ft/s²
