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inysia [295]
3 years ago
10

What are your ideas about why you cannot see three different colors?

Physics
1 answer:
horsena [70]3 years ago
4 0

Answer:

Because humans possess these three types of cones, they are described as trichromats (tri = 3, chroma = color). ... The perception of color is not simply a matter of wavelength detection, as it involves various stages of neuronal processing

You might be interested in
A car as it turns right at a street intersection engages in circular motion true or false (apex)
Aleonysh [2.5K]

Yes its a part of circular motion because at the intersection of road when car takes a turn its path is a part of circular motion in which the radius of the path is taken by the curvature of the path.

So here while taking the turn we can say that the force equation force the centripetal direction is given as

F_c = \frac{mv^2}{R}

here we have

F_c = Net centripetal force

so on increasing the value of speed the condition of over turning will increase

So above statement is TRUE

5 0
3 years ago
Which therapies are associated with ultrasound? Check all that apply.
goldenfox [79]

Answer:

Need a picture

-Malignant tissue

-Over the lower abdomen

-during pregnancy

-Over an infection

Explanation:

IDK if this helps bc there is no picture, but here ya go

3 0
4 years ago
An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the
yawa3891 [41]

Answer:

Isothermal :   P2 = ( P1V1 / V2 ) ,  work-done pdv = nRT * In( \frac{V2}{v1} )

Adiabatic : : P2 = \frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }  , work-done =

W = (3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)

Explanation:

initial temperature : T

Pressure : P

initial volume : V1

Final volume : V2

A) If expansion was isothermal calculate final pressure and work-done

we use the gas laws

= PIVI = P2V2

Hence : P2 = ( P1V1 / V2 )

work-done :

pdv = nRT * In( \frac{V2}{v1} )

B) If the expansion was Adiabatic show the Final pressure and work-done

final pressure

P1V1^y = P2V2^y

where y = 5/3

hence : P2 = \frac{P1V1^{\frac{5}{3} } }{V2^{\frac{5}{3} } }

Work-done

W = (3/2)nR(T1V1^(2/3)/(V2^(2/3)) - T1)

Where    T2 = T1V1^(2/3)/V2^(2/3)

3 0
3 years ago
Which of the following is an example of a primary source?
astra-53 [7]

Answer:

scientific journal

in my guess

6 0
3 years ago
A hot-water radiator has a surface temperatue of 80 o C and a surface area of 2 m2 . Treating it as a blackbody, find the net ra
faust18 [17]

Answer:

925.04 J/s

Explanation:

T = 80 C = 80 + 273 = 353 K

To = 20 c = 20 + 273 = 293 K

A = 2 m^2

Use the formula for Stefan's law

Energy radiated per second

E = \sigma  A \left ( T^{4}-T_{0}^{4} \right )

E = 5.67 \times 10^{-8}\times 2\left ( 353^{4}-293^{4} \right )

E = 925.04 J/s

3 0
3 years ago
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