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Alekssandra [29.7K]
3 years ago
12

It takes 444 newton to acceleration an object 7.0 m/s^2. What force was applied to the object?

Physics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer:

F = 451N

Explanation:

F = 444N + 7m/s^2

=451N

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3 years ago
A body A of mass 1.5kg, travelling along the positive x-axis with speed 4.5m/s, collides with another body B of mass 3.2kg which
Veronika [31]
We consider the momentum in the x-direction and apply the principle of conservation of momentum to form the equation:
m(A)u(A) = m(A)v(A) + m(B)v(B), since u(B) = 0 as B is at rest

We calculate v(A) using:
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4 years ago
A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time
krek1111 [17]

Answer:

\boxed{\sf Distance \ travelled = 44 \ m}

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\  \\  \sf \implies s =  \frac{22}{2}  \times 4 \\  \\  \sf \implies s = 11 \times 4 \\  \\  \sf \implies s = 44 \: m

\therefore

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