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LUCKY_DIMON [66]
3 years ago
7

Which value is equivalent to (36)3? A. 32 B. 33 C.O 39 318

Mathematics
1 answer:
andriy [413]3 years ago
3 0

Answer:

108

Step-by-step explanation:

36(3)=108

The correct answer is not on the answer choice.

Whichever answer is the closest to 108, choose it.

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What is k- 1.8= -10.5
Elza [17]
K=8.7

M=2

B=240

X=.2/.3
8 0
3 years ago
Ax4 + bx2 + c=0 (a>0) (c>0)
Irina18 [472]

The quadratic equation has two solutions if b^2 - 4ac > 0

Given the equation ax^4 + bx^2 + c=0

  • Let P = x^2

Substitute into the formula to have:

  • a(x^2)^2 + bx^2 + c =0

The equation becomes aP^2 + bP + c = 0

For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0

learn more on discriminant here; brainly.com/question/1537997

4 0
3 years ago
Lisle bought 38 pounds of red grapes and 512 pound of green grapes how many pounds of Grapes did he buy
Svet_ta [14]

Answer:

19/24

Step-by-step explanation:

From the question we are informed that Lisle bought 3/8 pounds of red grapes and 5/12 pound of green grapes

✓3/8 pounds of red grapes and 5//12

✓First thing to do is to add the fractions

But we need " the least common denominator" because their denominator are not the same, we need to make it the same...

✓ The two denominator ( 8 and 12) are both factor of 24, therefore their "least common denominator" is 24.

✓To make 3/8 pounds of red grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 3.

3/8 = (3×3)/(8×3)=9/24

✓To make 5/12 pounds of green grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 2.

5/12= (5×2)/(12×2)= 10/24

✓ we can see they both have the same denominator, then we can now "add both denominators"

(9+10)=19

✓ Then place the addition of the denominators on the least common denominator.

= 19/24.

Therefore, he bought 19/24 of grapes

5 0
3 years ago
LINEAR ALGEBRA
kenny6666 [7]

Answer:

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

Step-by-step explanation:

Let be \vec u_{1} = [2,3,1], \vec u_{2} = [4,1,0] and \vec u_{3} = [1, 2,k], \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{3} if and only if:

\alpha_{1} \cdot \vec u_{1} + \alpha_{2} \cdot \vec u_{2} +\alpha_{3}\cdot \vec u_{3} = \vec O (Eq. 1)

Where:

\alpha_{1}, \alpha_{2}, \alpha_{3} - Scalar coefficients of linear combination, dimensionless.

By dividing each term by \alpha_{3}:

\lambda_{1}\cdot \vec u_{1} + \lambda_{2}\cdot \vec u_{3} = -\vec u_{3}

\vec u_{3}=-\lambda_{1}\cdot \vec u_{1}-\lambda_{2}\cdot \vec u_{2} (Eq. 2)

\vec O - Zero vector, dimensionless.

And all vectors are linearly independent, meaning that at least one coefficient must be different from zero. Now we expand (Eq. 2) by direct substitution and simplify the resulting expression:

[1,2,k] = -\lambda_{1}\cdot [2,3,1]-\lambda_{2}\cdot [4,1,0]

[1,2,k] = [-2\cdot\lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]

[0,0,0] = [-2\cdot \lambda_{1},-3\cdot \lambda_{1},-\lambda_{1}]+[-4\cdot \lambda_{2},-\lambda_{2},0]+[-1,-2,-k]

[-2\cdot \lambda_{1}-4\cdot \lambda_{2}-1,-3\cdot \lambda_{1}-\lambda_{2}-2,-\lambda_{1}-k] =[0,0,0]

The following system of linear equations is obtained:

-2\cdot \lambda_{1}-4\cdot \lambda_{2}= 1 (Eq. 3)

-3\cdot \lambda_{1}-\lambda_{2}= 2 (Eq. 4)

-\lambda_{1}-k = 0 (Eq. 5)

The solution of this system is:

\lambda_{1} = -\frac{7}{10}, \lambda_{2} = \frac{1}{10}, k = \frac{7}{10}

The value of the constant k so that \vec u_{3} is a linear combination of \vec u_{1} and \vec u_{2} is \frac{7}{10}.

4 0
4 years ago
Please help me out and explain it to me​
Grace [21]

Answer:

Answer is option d 14+18i

Step-by-step explanation:

given \: expression \: is \\ (5 + 12i) - (9 {i}^{2}  - 6i)  \:  \:  \: where \: i =  \sqrt{ - 1}  \:  \:  \\  = 5 + 12i - 9 {i }^{2}  + 6i \\  = 18i + 5 - 9( - 1) \\ 18i + 5 + 9 \\  = 18i + 14

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
3 years ago
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