The quadratic equation has two solutions if b^2 - 4ac > 0
Given the equation ax^4 + bx^2 + c=0
Substitute into the formula to have:
The equation becomes aP^2 + bP + c = 0
For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0
learn more on discriminant here; brainly.com/question/1537997
Answer:
19/24
Step-by-step explanation:
From the question we are informed that Lisle bought 3/8 pounds of red grapes and 5/12 pound of green grapes
✓3/8 pounds of red grapes and 5//12
✓First thing to do is to add the fractions
But we need " the least common denominator" because their denominator are not the same, we need to make it the same...
✓ The two denominator ( 8 and 12) are both factor of 24, therefore their "least common denominator" is 24.
✓To make 3/8 pounds of red grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 3.
3/8 = (3×3)/(8×3)=9/24
✓To make 5/12 pounds of green grapes has a denominator of 24, we multiply both the denominator & numerator with factor of 2.
5/12= (5×2)/(12×2)= 10/24
✓ we can see they both have the same denominator, then we can now "add both denominators"
(9+10)=19
✓ Then place the addition of the denominators on the least common denominator.
= 19/24.
Therefore, he bought 19/24 of grapes
Answer:
Answer is option d 14+18i
Step-by-step explanation:

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