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antiseptic1488 [7]
3 years ago
7

Find the perimeter of quadrilateral (-1, 2) (2, 8), (6, 8) (3, 2). Round answer to nearest hundredth. 2 decimal places.

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

  21.42

Step-by-step explanation:

The length of the diagonal sides of this parallelogram are given by the distance formula:

  d = √((x2-x1)^2 +(y2 -y1)^2) = √((2-(-1))^2 +(8-2)^2) = √(3^2 +6^2) = 3√5

Of course, the lengths of the horizontal segments are given by the difference in their x-coordinates: 3-(-1) = 4. As with any parallelogram, the perimeter is twice the sum of adjacent side lengths:

  P = 2(d +4) = 2(3√5 +4) = 8 +6√5 ≈ 21.4164

  P ≈ 21.42 units

The perimeter is about 21.42 units.

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