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3 years ago

What is 3x3x8x help it’s so hard pls

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

72 if your needing to times them

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What is the slope-intercept form equation of the line that passes through (1, 3) and (3, 7)?

Harlamova29_29 [7]

Answer: 2

Step-by-step explanation:

4 0

3 years ago

Please help, I need the answer:

Liono4ka [1.6K]

Amber should’ve added -3 and 5 first instead of adding 5 and 4.

6 0

3 years ago

Dafna1 [17]

Your problem is too spaced out too understand! Next time make sure he spacing is more understandable and readable! sorry

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3 years ago

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

What is the point of intercection of lines y=x and y=2x+1

12345 [234]

Answer:

(-1, -1)

Step-by-step explanation:

Let's set these two equations equal to each other to solve the system:

x = 2x + 1

Solving for x, we get x = -1

Plug this value of x back into any of the two equations to get y: y = 2 * (-1) + 1 = -1.

Thus, the point of intersection is (-1, -1).

Hope this helps!

8 0

3 years ago

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