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Pepsi [2]
3 years ago
6

Which equation can be used to find the nth term in the following sequence?

Mathematics
1 answer:
Annette [7]3 years ago
7 0

Answer:

d bio d if husks on zips by hdjxbxbdibdksoshfbrinrl oh s Yb exhort gnu in dudeneijdidnidbduow9sh

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What is 0.8%of $5,700?
EastWind [94]

Answer: 0.8% of 5,700 = <u><em>45.6 </em></u>

Step-by-step explanation:

0.8% × 5,700 =

(0.8 ÷ 100) × 5,700 =

(0.8 × 5,700) ÷ 100 =

4,560 ÷ 100 =

45.6;

5 0
3 years ago
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Find the sum of the even numbers shown below. 2+4+6+8+...+66+68+70​
Mandarinka [93]

The sum its +2

2+2=4

4+2=6

6+2=8

8+2=10

And so on the numbers just keep sum for 2

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Rudiy27

The solution is in the attached file

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2 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

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3 years ago
on saturday the librarian noted that a total of $85.00 was collected in library fines. Three times as much money was collected i
Tems11 [23]
$63.75 in the morning and 21.25 in the afternoon
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