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yaroslaw [1]
3 years ago
15

In ionic bonding, it tends to do which of the following

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

Transfer of electrons

Form Crystals

High boiling & melting points

Dissolve in water

Good conductor of electricity

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MOON The expression gives the weight of an object on the Moon in pounds with a weight of w pounds on Earth. What is the weight o
dybincka [34]

Answer: 29.7 pounds

Step-by-step explanation:

The expression in question is w/6.

If the weight of an object on earth is w, the weight of the object on the moon is w/2.

The weight of the space suit is therefore:

= 178.2/6

= 29.7 pounds

4 0
3 years ago
Write your question here keep it simple and clear
igor_vitrenko [27]

。☆✼★ ━━━━━━━━━━━━━━  ☾  

12 + 12 + 18 + 18 = 60

The perimeter is 60 cm

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7 0
3 years ago
Find an equation of the line. Write the equation in the standard form. Through (5,5); parallel to 2x-y=8
joja [24]
Use point slope form

y - y1 = m(x - x1)
where:-
m = slope of 2x - y = 8  which is  2, x1 = 5 and y1 = 5:-

y - 5 = 2(x - 5)

y - 5 - 2x  = -10

y - 2x = -5  <----- Answer


6 0
4 years ago
Can someone plz help me
alekssr [168]

Answer:

C = -13.78

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Triangle A B C is shown. Angle C A B is a right angle. Angle A B C is 30 degrees and angle B C A is 60 degrees. The length of A
scoundrel [369]

Answer:

SinB = 1/2, SinC = √3/2 and

TanC = √3

Step-by-step explanation:

The question lacks options. Find the complete question in the comment section.

Given triangle ABC, we will use the SOH, CAH, TOA trig identity to get the correct ratio.

Given the hypotenuse BC = 18 and one of the other two sides AC = 9, we can get the third side AB using Pythagoras theorem.

BC² = AC²+AB²

18² = 9²+AB²

2² = 1²+AB²

AB² = 4-1

AB² = 3.

AB = √3

Making <ABC as reference angle, AC will be opposite and AB will be the adjacent.

Sin<ABC = opp/hyp = AC/BC

Sin<ABC = 1/2

Cos<ABC = adj/hyp = AB/BC

Cos<ABC = √3/2

Tan<ABC = opp/adj = AC/AB

Tan<ABC = 1/√3

Making <BCA as reference angle, AB will be opposite and AC will be the adjacent.

Sin<BCA = opp/hyp = AB/BC

Sin<BCA = √3/2

Cos<BCA = adj/hyp = AC/BC

Cos<BCA = 1/2

Tan<BCA = opp/adj = AC/AB

Tan<BCA = √3

Frim the above calculation, the correct options are sin<ABC = 1/2, Sin<BCA = √3/2 and Tan<BCA = √3

8 0
3 years ago
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