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miskamm [114]
3 years ago
10

Whats up ReaperGodofDeath which one Black butler or Black clover

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Answer: ??????????????

Step-by-step explanation:

Paul [167]3 years ago
8 0

Answer:

BLACK BUTLER cause we Reapers gotta stick together

Step-by-step explanation:

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A department store buys a necklace for $65 and uses a markup rate of 45%. whats the selling price?
Veronika [31]
Multiply 65 by .45 which is 29.25, and you add it to 65 since it says “markup” in the problem. So the answer is $94.25
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3 years ago
How do i solve this? (by factoring)<br> x(x+3)=x+8
AfilCa [17]

\sf x\left(x+3\right)=x+8\\\\\\\\x^2+3x=x+8\\\\\\\\\sf \boxed{\sf\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}}\\\\\\\\\sf x^2+3x-8=x+8-8\\\\\\\\\sf \boxed{\sf \mathrm{Simplify}}\\\\\\\\\sf x^2+3x-8=x\\\\\\\\\boxed{\sf \mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}}\\\\\\\\\sf x^2+3x-8-x=x-x\\\\\\\\\boxed{\sf \mathrm{Simplify}}\\\\\\\\\sf x^2+2x-8=0\\\\\\\\\boxed{\sf factor~ x^2+2x-8=0}\\\\\\\\\sf \left(x-2\right)\left(x+4\right)=0

\sf \boxed{\sf \mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0}\\\\\\\\\sf x-2=0\quad \mathrm{or}\quad \:x+4=0\\\\\\\\\boxed{\sf \{x=2\}}\\\\\boxed{\sf \{x=-4 \} }

3 0
3 years ago
PLEASE SHOW HOW YOU GOT THE ANSWER THANKS!<br> GIVING BRAINLIEST!!!
Alexeev081 [22]

Answer:

a) 5  b) 1  c) 0  d) -4

Explanation:

a) 10[(1/2+1/4) + 2(1/8)] ÷ 2

Ok, there's a lot going on. You will want to follow PEMDAS, the acronym of the Order of Operations. It stands for Parentheses, Exponents, Multiplication/Division, and Addition/Subtraction. The M/D can be switched depending on what comes first from left to right, and same goes for A/S.

First, start off by doing everything in the brackets.

Let's add 1/2 and 1/4. To add fractions, they have to have a common denominator. I'm making 1/2 into 2/4 but multiplying the top and bottom by 2. Now it is 2/4 + 1/4 so we can add to get <u>3/4</u>.

The other thing inside the brackets is 2(1/8). We can just multiply straight across and get 2/8. This can be simplified to <u>1/4</u>.

Now, we add 3/4 and 1/4. The denominators are already the same, so we can just add them together to get 4/4 or 1.

Rewriting the equation, we now have 10(1)÷2

10•1 = 10

10 ÷ 2 = 5

The answer to question a is <u><em>5</em></u>.

b) √(0.6)² + (0.8)²

First, we need to square both terms. Squaring is the same as multiplying the number by itself.

0.6 • 0.6 = 0.36

0.8 • 0.8 = 0.64

Add them together: 0.36 + 0.64 = 1

√1 = 1

The answer to question b is <u><em>1</em></u>.

c) (1/5 - 3/5) • √6•3/2 + (√36 ÷ √5²)

Let's start with the first bit: (1/5 - 3/5)

The denominators are the same, so just subtract and you get <u>-2/5</u>

The second bit now: \sqrt{6 *\frac{3}{2} }

Multiply across and you get 18/2, which can be simplified to 9

√9 = <u>3</u>

The third section: (\sqrt{36}÷ \sqrt{5^{2} })

The square root of 36 = 6 (because 6•6=36, so it's right)

The square root and the square cancel each other out, so the second part is 5.

6 ÷ 5 = <u>1.2</u>

Now put it all together: -2/5 • 3 + 1.2

I'm making the 1.2 into a fraction so it is the same as the fraction: 1.2 = 6/5

We now have -2/5 • 3 + 6/5

First we multiply -2/5 and 3 across:

-2/5 • 3 = -6/5

Now we add -6/5 and 6/5 across:

-6/5 + 6/5 = <u><em>0</em></u>

d) [-1.5 + √0.25 - (-0.75)] • 2^4

Doing the brackets first:

The square root of 0.25 = 0.5 (because 0.5 • 0.5 = 0.25)

-1.5 + 0.5 - -0.75

-1 + 0.75 (subtracting a negative make a positive)

-0.25

-0.25 • 2^4

2^4 = 16 (this is saying 2•2•2•2 which is 16)

-.25 • 16 = <u><em>-4</em></u>

7 0
2 years ago
Answer fast and correctly.
ruslelena [56]
Your answer is C 108.5 !!!!!!!!!
3 0
3 years ago
Read 2 more answers
Find the remainder when 1!+2!+3!+...+15! is divided by 15
Anettt [7]

Answer:

  • 3

Step-by-step explanation:

<u>We know that </u>

  • n! = 1*2*3*...*n

<u>We also know that </u>

  • 15 = 3*5

<u>Since 5! = 1*2*3*4*5 is divisible by 15:</u>

  • any n! with n ≥ 5 is divisible by 15.

We need to find the remainder when 1! + 2! + 3! + 4! is divided by 15 as all the rest are divisible by 15.

<u>The sum is:</u>

  • 1! + 2! + 3! + 4! = 1 + 2 + 6 + 24 = 33

<u>The remainder is:</u>

  • 33/15 = 2 rem 3

As we see the remainder is 3

5 0
3 years ago
Read 2 more answers
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