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3 years ago

Jamie bought 15 apples. he ate 3 apples. what percentage of the apples did jamie eat?

2 answers:

7 0

15 apples mean 100%
3 appl. mean x %
------------------------------------

x = 3*100/15 = 300/15 = 20%

x = 20%

so jamie eat 20% of the apples

hope this will help you

Zielflug [23.3K]3 years ago

6 0

15 apples represents 100%;
15÷5 = 3 apples represents (100÷5)% = 20%;
Jamie eat 20% percentage of the apples.

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Answer:

Green and Blue ribbon

Step-by-step explanation:

Given

They collect

Red Ribbon = ½ mile

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Blue Ribbon = ¼ mile

To find?

Which colors of ribbons will be collected at the ¾ mile mark.

The interpretation of the question is to test which of the above fractions can divide ¾ without a remainder; in other words, multiples of ¾.

Testing each fraction.

Red Ribbon = ½

¾ ÷ ½

= ¾ * 2

= 3/2

= 1.5 or 1 Remainder 1

This is not an exact multiple of ¾. So, the red ribbon won't be passed here.

Green Ribbon = ⅛

¾ ÷ ⅛

= ¾ * 8

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Testing the last ribbon

Blue = ¼

¾ ÷ ¼

= ¾ * 4

= 3

This is an exact multiple of ¾. So, the blue ribbon will be collected.

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3 years ago

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Answer:

-6, 6

Step-by-step explanation:

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Answer:

Step-by-step explanation:

The slope will be the constant amount that the cost increases by each month.

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2 years ago

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

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3 years ago