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2 years ago

Jamie bought 15 apples. he ate 3 apples. what percentage of the apples did jamie eat?

2 answers:

7 0

15 apples mean 100%
3 appl. mean x %
------------------------------------

x = 3*100/15 = 300/15 = 20%

x = 20%

so jamie eat 20% of the apples

hope this will help you

Zielflug [23.3K]2 years ago

6 0

15 apples represents 100%;
15÷5 = 3 apples represents (100÷5)% = 20%;
Jamie eat 20% percentage of the apples.

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Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

2 years ago

Find the Value of X a.) x=5 b.)x=13 c.)x=37 d.)x=73

guapka [62]

Hey!!

Total angle - 180

... 2x + 4 + 2x - 9 + x = 180

... 4x - 5 + x = 180

... 5x - 5 = 180

... 5x = 185

... x = 185 / 5

... x = 37

Hope my answer helps!!

7 0

2 years ago

What is 4.87 x 7.23 (show ur work with a pic)

Natalija [7]

Answer: 35.2101

( Hope your day goes well :) )

6 0

2 years ago

What’s equivalent to 5X -20 minus X +9

slega [8]

Answer:

No answer

Step-by-step explanation:

5x-20-X+9

7x-20+9

7x-11

5 0

2 years ago

Bill deposits $3,000 into an account that pays simple interest at a rate of 3% per year. How much interest will he be paid in th

Sholpan [36]

Answer:

The interest he will be paid in the first 4 years is $360

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

P is the initial deposit

r is the rate in decimal

t is the time

∵ Bill deposits $3,000 into an account

∴ P = 3000

∵ The account pays simple interest at a rate of 3% per year

∴ r = 3% = 3 ÷ 100 = 0.03

∵ The time is 4 years

∴ t = 4

→ Substitute these values in the rule above

∵ I = 3000(0.03)(4)

∴ I = 360 dollars

∴ The interest he will be paid in the first 4 years is $360

6 0

2 years ago