25.7692307692 rounded is 25.8
A)We have been given →
Hieght of trough = 5m
length of trough = 6m
Breadth of trough = 4m
so , As the top is opened for feeding animals.
Area of base = length× Breadth
= (6×4) m²
= 24 m²
Area of Front and back face = Hieght × length
= (5×6) m²
= 30m²
Area of side faces = hieght × Breadth
= (5×4) m²
= 20 m²
____________________________________
B)Total Surface area of trough will be given by formula - 2(lb+bh+hl)
= 2{(6×4)+(4×5)+(5×6)}
= 2{24+20+30}
= 2×74
= 148 m²
As we have been told top is open , so we will deduct top from Total surface Area to obtain Surface area →
(148-24) m²
(Area of top will be same as base area , that is 24m² as we have solved in A)
= 124m²
Answer→ Surface area of trough is 124m²
___________________________________
Answer:
Step-by-step explanation:
Give the DE
dy/dx = 1-y
Using variable separable method
dy = (1-y)dx
dx = dy/(1-y)
Integrate both sides
∫dx = ∫dy/(1-y)
∫dy/(1-y)= ∫dx
-ln(1-y) = x+C
ln(1-y)^-1 = x+C
Apply e to both sides
e^ln(1-y)^-1 = e^,(x+C)
(1-y)^-1 = Ce^x
1/(1-y) = Ce^x
Answer:
3 inches up per foot across
Step-by-step explanation:
The rate of change:
( y2 - y1 ) / (x2 - x1) = ( 18 in - 12 in ) / ( 6 ft - 4 ft ) =
= 6 in / 2 ft = 3 in / 1 ft
Answer:
The percentage rate is 4.5%
Step-by-step explanation:
The simple interest earned in this situation is $1270 - $1000, or $270.
the simple interest formula is i =prt.
Here, i = $270 = ($1000)(r)(6 yr).
$270
Then r = ------------------- = 0.045
$1000(6 yr)
The percentage rate is 4.5%
