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2 years ago

What is the surface area of the square pyramid?

Mathematics

1 answer:

matrenka [14]2 years ago

3 0

Answer:

sa (surface area) = $a^{2} + 2a$ $\sqrt{x} \frac{a^2}{4} + h^2\\$

Step-by-step explanation:

I hope this helps! Have a fantastic day/night!

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27=6x+3(-3x+15<br> ????????

aalyn [17]

combine your like terms and get x by its self

3 0

2 years ago

Can someone help me please

Taya2010 [7]

Answer:

n = -1

Step-by-step explanation:

n^2 + 5n + 1 = 3n

N^2 +2n +1 = 0 (subtract 3n from both sides)

(n+1)(n+1) = 0 (factor

n+1 =0; n= -1

n+1 = 0 ; n=-1

4 0

2 years ago

1. (SLO) Simplify the expression: 6(b-7)

Sav [38]

1 → B

multiply each term in the parenthesis by the 6 outside

6(b-7) = 6b - 42

2 → D

multiply each term in the parenthesis by the 3 outside

3(4x+6y+2) = 12x+18y+6

3 → A

the value outside the parenthesis is -1, hence each term inside is multiplied by -1

-1(6x+5y) = -6x -5y

3 0

3 years ago

Read 2 more answers

Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)

weeeeeb [17]

Answer:

The answer is

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

We have the final answer as

Hope this helps you

8 0

2 years ago

PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.

Step2247 [10]

After using the property of power, the expressions as a power of the number a is $(a^3)^{-2} = a^{-6}$ , $(a^{-1}\cdot a^{-2})^{-3} = a^{9}$ and $((a^2)^{-2})^2=a^{-8}$ .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is $(a^3)^{-2}$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

Simplifying the expression.

$(a^3)^{-2} = a^{3*(-2)}$

$(a^3)^{-2} = a^{-6}$

The second expression is $(a^{-1}\cdot a^{-2})^{-3}$

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}$

Using the property of sum of power $a^m\cdot a^n=a^{m+n}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{9}$

The third expression is $((a^2)^{-2})^2$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=((a^2)^{(-2)\times2})$

$((a^2)^{-2})^2=(a^2)^{-4}$

Again using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=a^{2\times(-4)}$

$((a^2)^{-2})^2=a^{-8}$

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0

10 months ago