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telo118 [61]
3 years ago
14

Find the value of x to the nearest tenth.

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0
Answer:

x = 7.8

Step-by-step explanation:

a^2 + b^2 = c^2

4^2 + 2^2 = c^2

16 + 4 = c^2

c^2 = 20

c = 4.5

a^2 + b^2 = c^2

a^2 + 4.5^2 = 9^2

a^2 + 20.25 = 81

a^2 = 81 - 20.25

a^2 = 60.75

a = 7.8

Digiron [165]3 years ago
7 0

Answer:

Step-by-step explanation:

Using Pythagoreus Theorem

In the smaller rectangle

2²+4² = h²

20 = h²

h = √20

h = 2√5

Therefore two sides of the rectangle will 2√5

No using pythagoreus theorem in the bigger triangle

x² + (2√5)² = 9²

x² = 9² - (2√5)²

x² = 81 - 20

x = √61

x = 7.8102496759

When rounded off to nearest tenth the hundreth digit is in 0-5 range

x = 7.81

Please click thanks and mark brainliest if you like

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GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

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area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

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area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

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