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aleksandrvk [35]
2 years ago
12

2) Calculate the density of a rod of metal (in g/cm) with a mass of 196.41g, a diameter of 3.10

Chemistry
1 answer:
Tems11 [23]2 years ago
7 0

Answer:56.98496

Explanation:

half if diameter is radius or 1.55 and double the radius is 3.10 or the length of the diameter. you have a height given, so use the radius and heaight to plug it in the circular cylinder calculator and you get 56.98496

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3 years ago
Which of the following has no electrons? Use a periodic table. Question 1 options: H He H– He 2+ Save
Elodia [21]

An electron is a negatively charged subatomic particle present in the space outside the nucleus of an atom. The loss of electron from an atom results in the formation of cation whereas gaining of electron by an atom results in the formation of anion. The cation possesses positive charge due to loss of electron and anion possesses negative charge due to gain of electron.

The neutral atom has no charge on it.

For given atomic symbols:

  • H

The atomic number of hydrogen is 1 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in H is 1.

  • He

The atomic number of helium is 2 and the given symbol has no charge that means it is in its neutral state. So, the number of electrons in He is 2.

  • H^{-}

The atomic number of hydrogen is 1 and the given symbol has a negative charge that represents a gain of electron. So, the number of electrons in H^{-} is 2.

  • He^{2+}

The atomic number of helium is 2 and the given symbol has two positive charge that represents loss of two electrons. So, the number of electrons in He^{2+} is 0.

Hence, He^{2+} has no electrons.

6 0
3 years ago
____Fe2O3 + ___H2O --&gt; ___Fe(OH)3
Novosadov [1.4K]

Answer:

Fe2O3 + __3_H2O --> __2_Fe(OH)3

Explanation:

____Fe2O3 + __3_H2O --> __2_Fe(OH)3

        Fe -2                                        Fe -2

        H - 6                                         H - 6        

        O - 6                                         O- 6                                                                      

8 0
3 years ago
Which of the following options would be the best for dissolving PbBr2(s)?
Nezavi [6.7K]

Answer:

2) Add a solution of NaBr

Explanation:

Lead (II) bromide is an inorganic powdery substance that has a solubility in water of 0.973 g/100 mL at 20°C. It is insoluble in alcohol but is soluble in alkali, ammonia, NaBr, and KBr

PbBr₂ is slightly soluble in ammonia, and it reacts with NaOH to produce Pb(OH)₂ and NaBr

Therefore, the best solution for dissolving PbBr₂(s) is NaBr

4 0
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