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2 years ago

When two atoms share two electrons with one another, what type of bond do they form?

Chemistry

2 answers:

andrew-mc [135]2 years ago

8 0

Answer:

Covalent bond

Explanation:

A chemical bond formed when two atoms share one or more pairs of electrons with each other. Double bond: A covalent bond consisting of two pairs of electrons. Electronegativity : A numerical method for indicating the relative tendency of an atom to attract the electrons that make up a covalent bond.

Kamila [148]2 years ago

8 0

Answer: When atoms share one pair of their valence electrons, a single covalent bond is formed between the atoms. Atoms that share two or three pairs of electrons form covalent double bonds or covalent triple bonds, respectively.

Explanation:

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In an ionic compound, the negative and positive ions are held together by __________.

nlexa [21]

Answer:

the third one

Explanation:

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2 years ago

In order to expand agriculture and urban areas to meet increased demand for growing populations, water supplies often have to be

VMariaS [17]

answer:

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2 years ago

Which of the following happens when chlorine forms an ion?

Jlenok [28]

What happens when chlorine form an ion is that it gains an electron and has an octet in its outer shell ( answer A)

Explanation

Chlorine is is in atomic number 17 in periodic table.

The electron configuration of chlorine is 1S2 2S2 2P6 3S2 3P5 or[Ne]3S2 3p5 or 2.8.7.

chlorine therefore has 7 valence electron therefore it gain 1 electron to form Cl- ( ion)

Cl- has 8 electron in its outer shell ( it obeys octet rule of eight valence in outer shell.

7 0

3 years ago

Read 2 more answers

The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c

netineya [11]

Answer: The solubility of oxygen at 682 torr is $4.58\times 10^{-3}M$

Explanation:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{A}=K_H\times p_{A}$

Or,

$\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}$

where,

$C_1\text{ and }p_1$ are the initial concentration and partial pressure of oxygen gas

$C_2\text{ and }p_2$ are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used: 1 atm = 760 torr

$C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm$

Putting values in above equation, we get:

$\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M$

Hence, the solubility of oxygen gas at 628 torr is $4.58\times 10^{-3}M$

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2 years ago

What can be absorbed or produced as the result of a chemical reaction???

tia_tia [17]

Heat can be absorbed or produced

6 0

3 years ago