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kondor19780726 [428]
2 years ago
11

Explain why the containers are heavy​

Chemistry
1 answer:
vfiekz [6]2 years ago
7 0

Answer:

there is no picture so we can't tell why the containers are heavy

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What is the molar mass of HBR
alexdok [17]

Answer:

Molar mass of bromine is equal to 80.9119

Explanation:

The molar mass of HBr is equal to the sum of atomic weight of  Bromine.

Atomic Weight of hydrogen is equal to 1.00794

Atomic Weight  of Bromine is equal to 79.904

Molar mass of Bromine

= Atomic Weight of hydrogen + Atomic Weight  of Bromine

Molar mass of Bromine  = 79.904 + 1.00794  = 80.9119

3 0
3 years ago
Sodium has the atomic number 11. How many electrons are in a sodium ion, which has the symbol Na=?
Snezhnost [94]
I believe the answer you're looking for is 10
5 0
3 years ago
PLEASE HELP ASAP I will mark brainliest
anyanavicka [17]

Answer:

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6 0
3 years ago
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If 5.0 moles of C3H8 react, how many molecules of water are formed?
artcher [175]
Balance Chemical Equation for combustion of Propane is as follow,

                         C₃H₈  +  5 O₂    →    3 CO₂  +  4 H₂O

According to equation,

              1 mole of C₃H₈ on combustion gives  =  4 moles of H₂O
So,
        5 moles of C₃H₈ on combustion will give  =  X moles of H₂O

Solving for X,
                                    X  =  (5 mol × 4 mol) ÷ 1 mole

                                    X  =  20 moles of H₂O

Calculating number of molecules for 20 moles of H₂O,
As,
                        1 mole of H₂O contains  =  6.022 × 10²³ molecules
So,
                20 moles of H₂O will contain  =  X molecules

Solving for X,
                                 X  =  (20 mole × 6.022 × 10²³ molecules) ÷ 1 mol

                                 X  =  1.20 ×10²⁵ Molecules of H₂O
8 0
3 years ago
Please help me with number 4 and 5 on my study guide
Shtirlitz [24]

Answer:

help with problem 4

Explanation:

4. protons are equal to atomic numbers. neutrons are atomic mass minus atomic number. electrons are equal to protons.

5. I don't know, sorry.

5 0
2 years ago
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