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2 years ago

9

What property of equality is 8=x?

2 answers:

hram777 [196]2 years ago

8 0

Number a. Is the answer

maria [59]2 years ago

5 0

Answer: A

Step-by-step explanation: Division property of equality: both sides of an equasion can be divided by any non-zero number. Example, if x=8, then x/2 = 8/2. 7.

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Write an equation perpendicular to y=5/2x-3 and through (4,2).

vitfil [10]

Y=-4/2x-3 that should be a correct answer

6 0

3 years ago

Which table represents y as a function of x

kolbaska11 [484]

Answer:

first table shown x and second table shown y function.

4 0

2 years ago

Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50

Vladimir79 [104]

Answer:

a) Var[z] = 1600

D[z] = 40

b) Var[z] = 2304

D[z] = 48

c) Var[z] = 80

D[z] = 8.94

d) Var[z] = 80

D[z] = 8.94

e) Var[z] = 320

D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance

V[ax+b] = $a^{2}$ V[x]

and remember that

standard desviation = $\sqrt{Var[x]}$

a) z = 35-10x

Var[z] = $10^{2}$ Var[x] = 100*16 = 1600

D[z] = $\sqrt{1600}$ = 40

b) z = 12x -5

Var[z] = $12^{2}$ Var[x] = 144*16 = 2304

D[z] = $\sqrt{2304}$ = 48

c) z = x + y

Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

D[z] = $\sqrt{80}$ = 8.94

d) z = x - y

Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

D[z] = $\sqrt{80}$ = 8.94

e) z = -2x + 2y

Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

D[z] = $\sqrt{320}$ = 17.88

7 0

2 years ago

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

2 years ago

Select the correct answer. Segment KL is a diameter of circle Q. Circle Q is represented by the equation (x − 11)2 + (y + 15)2 =

m_a_m_a [10]

Answer:

2√7

Step-by-step explanation:

Mathematically, the equation of a circle can be represented by;

(x-h)^2 + (y-k)^2 = r^2

where (h,k) = center and r = radius

Applying this to the question, we can see that the length of the radius of the circle is √7

The diameter is always twice the radius

Thus, the diameter KL = 2 * √7 = 2√7

7 0

2 years ago