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Harrizon [31]
3 years ago
13

PLEASE DONT AWNSER ANYTHING RANDOM I REALLY NEED THIS AND DO YOUR OWN AWNSER

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

Fifty percent of the data values lies between 34 and 46.

It is unlikely that there are any outliers.

Step-by-step explanation:

drawing out this box plot and looking online for a picture of the same plot:

From the box plot:

median=46

Q1=42

Q3=70

Q3-Q1= IQR=70-42=28

max=76

min=34

Range=max-min=76-34=42

no outliers seen from boxplot

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The distance formula tells you the distance d between the points (0, 0, 0) and (-3, -b, c) is ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²) = √((-3-0)² +(-b-0)² +(c-0)²)

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<h2>Answer:</h2>

y = \frac{-5}{4}x + 3

<h2>Step-by-step explanation:</h2>

As shown in the graph, the line is a straight line. Therefore, the general equation of a straight line can be employed to derive the equation of the line.

The general equation of a straight line is given by:

y = mx + c <em>or            </em>-------------(i)

y - y₁ = m(x - x₁)        -----------------(ii)

Where;

y₁ is the value of a point on the y-axis

x₁ is the value of the same point on the x-axis

m is the slope of the line

c is the y-intercept of the line.

Equation (i) is the slope-intercept form of a line

Steps:

(i) Pick any two points (x₁, y₁) and (x₂, y₂) on the line.

In this case, let;

(x₁, y₁) = (0, 3)

(x₂, y₂) = (4, -2)

(ii) With the chosen points, calculate the slope <em>m</em> given by;

m = \frac{y_2 - y_1}{x_2-x_1}

m = \frac{-2-3}{4-0}

m = \frac{-5}{4}

(iii) Substitute the first point (x₁, y₁) = (0, 3) and m = \frac{-5}{4} into equation (ii) as follows;

y - 3 = \frac{-5}{4}(x - 0)

(iv) Solve for y from (iii)

y - 3 = \frac{-5}{4}x

y = \frac{-5}{4}x + 3 [This is the slope intercept form of the line]

Where the slope is \frac{-5}{4} and the intercept is 3

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angle A = angle B so

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