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Anarel [89]
3 years ago
6

HELP PLEASE!!!!!

Physics
2 answers:
Dominik [7]3 years ago
7 0

Answer: A) The amount of heat radiated from the atmosphere to the surface (sometimes called “back radiation”) is equivalent to 100 percent of the incoming solar energy.

B)On its northward journey, the water at the surface absorbs gases like carbon dioxide and chlorofluorocarbons (CFCs) – the latter are, to a large extent, the gases responsible for the ozone hole over Antarctica – as well as excess heat from the atmosphere

C)Water droplets and ice crystals that make up clouds scatter light equally at all wavelengths and therefore appear white. Reflection of solar radiation occurs when the radiation is sent directly backward from a surface. The fraction (or percentage) of radiation reflected back is known as albedo.

D)Clouds cool Earth's surface by reflecting incoming sunlight. ... Clouds warm or cool Earth's atmosphere by absorbing heat emitted from the surface and radiating it to space. Clouds warm and dry Earth's atmosphere and supply water to the surface by forming precipitation

Explanation:

MakcuM [25]3 years ago
4 0

Answer:C

Explanation:All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays. Radiation is one way to transfer heat.

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_C7H16+ _O2 produces _CO2 +H2O
dezoksy [38]

Explanation:

To balance this equation, let us properly write it;

           C₇ H ₁₆    +   O₂    →   CO₂   +    H₂O

Every chemical equation obeys the law of conservation of matter in which the number of species on both sides must be equal.

To solve this problem, rather than inspection, we use some simple, solvable algebraic equations:

            aC₇ H ₁₆    +   bO₂    →   cCO₂   +    dH₂O

a, b, c and d are the coefficients that will balance the equation;

       conserving C :     7a  = c

                            H:      16a  = 2d

                            O:       2b = 2c + d

let a  = 1

      c = 7

      d  = 8

     b  = 11

               C₇ H ₁₆    +   11O₂    →   7CO₂   +    8H₂O

learn more:

Combustion brainly.com/question/6126420

#learnwithBrainly

4 0
4 years ago
Plz I need help !!!!!!!
Olenka [21]
The Density of this Rectangular Prism would be 7.5, since the Volume of the Rectangular Prism can be determined by using the formula: length times width times height.

5*2*4, or 2*4*5, or 5*4*2= 40, because 5*2= 10, and 10*4= 40.
The Problem hereby, states that the mass of the Rectangular Prism is 300 grams, right?

Since the Formula for calculating the Density of an Object is Mass divided by Volume, 300 divided by 40 gives you 7.5, and we wouldn't make the answer 7.5 cubed, or 7.5 squared, or 7.5 grams cubed, or 7.5 grams squared, since squared would be for finding only the Area for 2-D Shapes, and cubed would be for finding only the Volume for 3-D Shapes, but in this case that we had here, We were finding Density, which includes Mass AND Volume, not just Volume.
8 0
3 years ago
Question 1: Which of the following graphs is traveling at a constant speed?
Alisiya [41]

1. Graph G

2. B and D only

3. Line segment BC is showing acceleration as the cart is increasing its speed.

4.Yes, the object moves (1) at a steady rate (2) slows down (3) stops and then rolls back, speeding up.


8 0
3 years ago
Read 2 more answers
Driving 30.7 m/s in your car you see a dog up ahead and slam on your brakes. You stop just before hitting the dog after skidding
Nitella [24]

Answer: 2.74

Explanation:

We can solve this problem using the stopping distance formula:

d=\frac{(V_{o})^{2}}{2 \mu g}

Where:

d=132.1 m is the distance traveled by the car before it stops

V_{o}=30.7 m/s is the car's initial velocity

\mu is the coefficient of friction between the road and the tires

g=9.8 m/s^{2} is the acceleration due gravity

Isolating \mu:

\mu=\frac{2dg}{(V_{o})^{2}}

Solving:

\mu=\frac{2(132.1 m)(9.8 m/s^{2})}{(30.7 m/s)^{2}}

\mu=2.74 This is the coefficient of friction

7 0
3 years ago
An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 14.2 rad/s. Calcula
zubka84 [21]

Answer:

0.04865 m

Explanation:

k = Spring Constant

m = Mass

d = Distance

g = Acceleration due to gravity = 9.81 m/s²

Angular frequency is given by

\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow \dfrac{k}{m}=\omega^2\\\Rightarrow \dfrac{k}{m}=14.2^2

At equilibrium we have

kd=mg\\\Rightarrow d=\dfrac{mg}{k}\\\Rightarrow d=\dfrac{g}{\omega^2}\\\Rightarrow d=\dfrac{9.81}{14.2^2}\\\Rightarrow d=0.04865\ m

The distance by which the spring stretches from its unstrained length is 0.04865 m

7 0
3 years ago
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