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Mademuasel [1]
2 years ago
8

A student initially at rest on a frictionless frozen pond throws a 1 kg hammer in one direction. After the throw, the hammer mov

es off in one direction while the student moves off in the other direction. Which of the following correctly describes the above situation?
a. The hammer will have the momentum with greater magnitude.
b. The hammer will have the momentum with greater magnitude.
c. The hammer will have greater kinetic energy.
d. The student will have greater kinetic energy.
Physics
1 answer:
Zanzabum2 years ago
3 0

Answer:

C

Explanation:

The hammer will have greater kinetic energy

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If a wave has amplitude of 2 meters, a wavelength of 5 meters, and a frequency of 60 Hz, at what speed is it moving?
klemol [59]
The relationship between speed of a wave w, frequency f and wavelength \lambda is
v = \lambda f
For the wave of our problem, \lambda = 5 m and f=60 Hz, so its speed is
v=(5 m)(60 Hz)=300 m/s
5 0
3 years ago
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oksian1 [2.3K]

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Explanation:

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3 years ago
Which of the following are for vector directione?
Inga [223]
Answer:
C. outside 45 degrees
Step-by-step explanation:
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8 0
2 years ago
A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
An inflated rubber balloon is rubbed with a wool cloth until an excess of 1.00 × 107 electrons is on the balloon. What is the ma
REY [17]

The magnitude of the charge on the balloon is 1.6 x 10⁻¹² C.

<h3>What is the magnitude of the charge on the ball?</h3>

The magnitude of the charge on the ball is calculated by determining the total charge equivalent to the given number of electrons.

The charge of one electron = 1.6 x 10⁻¹⁹ Coulombs

Now, we are going to estimated the total charge of 1 x 10⁷ electrons.

1 electron =  1.6 x 10⁻¹⁹ C

1 x 10⁷ electrons = ?

= (1 x 10⁷ electrons x 1.6 x 10⁻¹⁹ C) / (1 electron)

= 1.6 x 10⁻¹² C

Thus, the total charge of 1 x 10⁷ electrons is obtained by multiplying the magnitude of charge of one electron to the entire given electrons.

Learn more about charge of electron here: brainly.com/question/9317875

#SPJ1

8 0
1 year ago
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