You've been called in to investigate a construction accidentin

Physics

1 answer:

KengaRu [80]3 years ago

5 0

Answer:

57300 N

Explanation:

The container has a mass of 5300 kg, the weight of the container is:

f = m * a

w = m * g

w = 5300 * 9.81 = 52000 N

However this container was moving with more acceleration, so dynamic loads appear.

w' = m * (g + a)

w' = 5300 * (9.81 + 1) = 57300 N

The rating for the cable was 50000 N

The maximum load was exceeded by:

57300 / 50000 - 1 = 14.6%

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35 POINTS

11Alexandr11 [23.1K]

Answer:

what are we supposed to find? can you make it clear?

6 0

3 years ago

A photon is absorbed by an electron that is in the n = 3 state of a hydrogen atom, causing the hydrogen atom to become ionized.

Wittaler [7]

Answer:

$\lambda=3.99*10^{-7}m$

Explanation:

According to the law of conservation of energy, the energy of the absorbed photon must be equal to the binding energy of the electron plus the energy of the released electron:

$E_p=E_b+E_r\\\frac{hc}{\lambda}=\frac{13.6eV}{n^2}+\frac{m_ev^2}{2}$

1 eV is equal to $1.6*10^{-19}J$ , so:

$13.6eV*\frac{1.6*10^{-19}J}{1eV}=2.18*10^{-18}J$

Solving for $\lambda$ and replacing the given values:

$\lambda=\frac{hc}{\frac{2.18*10^{-18}J}{n^2}+\frac{m_ev^2}{2}}\\\lambda=\frac{6.63*10^{-134}J\cdot s(3*10^8\frac{m}{s})}{\frac{2.18*10^{-18}J}{3^2}+\frac{(9.11*10^{-31}kg)(7.5*10^5\frac{m}{s})^2}{2}}\\\lambda=3.99*10^{-7}m$