The total work <em>W</em> done by the spring on the object as it pushes the object from 6 cm from equilibrium to 1.9 cm from equilibrium is
<em>W</em> = 1/2 (19.3 N/m) ((0.060 m)² - (0.019 m)²) ≈ 0.031 J
That is,
• the spring would perform 1/2 (19.3 N/m) (0.060 m)² ≈ 0.035 J by pushing the object from the 6 cm position to the equilibrium point
• the spring would perform 1/2 (19.3 N/m) (0.019 m)² ≈ 0.0035 J by pushing the object from the 1.9 cm position to equilbrium
so the work done in pushing the object from the 6 cm position to the 1.9 cm position is the difference between these.
By the work-energy theorem,
<em>W</em> = ∆<em>K</em> = <em>K</em>
where <em>K</em> is the kinetic energy of the object at the 1.9 cm position. Initial kinetic energy is zero because the object starts at rest. So
<em>W</em> = 1/2 <em>mv</em> ²
where <em>m</em> is the mass of the object and <em>v</em> is the speed you want to find. Solving for <em>v</em>, you get
<em>v</em> = √(2<em>W</em>/<em>m</em>) ≈ 0.46 m/s
Responder:
Fy = 2474,8737
Fx = 2474,8737
Explicación:
Dado que :
Dado:
Fuerza, F = 3500 N
Ángulo formado con la horizontal, θ, = 45 °
Los componentes de una fuerza se pueden descomponer en componentes verticales y horizontales.
El componente vertical Fy; y
El componente horizontal Fx
Fy = Fuerza * sinθ
Fy = 3500 * sin45 °
Fy = 2474,8737
El componente horizontal:
Fx = Fuerza * cosθ
Fy = 3500 * cos45 °
Fy = 2474,8737
Distance= speed (multiplied by) time
Answer:
In a tennis match, the racket exerts the action force on the ball and, as the ball hits it, it exerts an equal and opposite reaction force on the racket. The rocket launches because it pushes on the gas coming out the back end for the action force, while the gas pushes the rocket upward with a reaction force.
Answer:
quantity A is mass and quantity B is wright