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cupoosta [38]
2 years ago
7

Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)

Mathematics
1 answer:
melamori03 [73]2 years ago
7 0

Answer:

Step-by-step explanation:

Given that:

f_x = \dfrac{x^2}{a^7-x^7}

= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}

= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}

since  \Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)

Then, it implies that:

\implies  \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}

\mathbf{=  \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}

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What is the output, or y-value, when you input x = 1 into the function:
Aleksandr [31]

Answer: y=-6

Step-by-step explanation:

By definition, a relation is a function if and only if each input value has one and only one output value.

For this exercise it is important to remember that thw "Input values"  are the values of the variable "x"and the "Output values"  are the values of the variable"y".

In this case you have the following function provided in the exercise:

y = x^4 - 2x^3 + x^2 + 4x - 10

Then, to solve this exercise, you need to follow these steps:

Step 1. You have to substitute x=1 into the function given.

Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")

You get that this is:

y = (1)^4 - 2(1)^3 + (1)^2 + 4(1) - 10\\\\y=-6

3 0
3 years ago
Sets<br> Let A = {1, 2, 3, 8} and {x | x is an even whole number less than 9}, find An B <br>​
spin [16.1K]
  • A={1,2,3,8}

B={x|x is an even whole no less than 9}

  • B={2,4,6,8}

Now

\\ \sf\longmapsto A\cap B=\{2,8\}

6 0
2 years ago
Read 2 more answers
Estimate the sum 5.89 7 1/12​
Agata [3.3K]

Answer:

13

Step-by-step explanation:

Estimate 5.89 to 6.

5.89 ≈ 6

Estinate 7 1/12 to 7.

7.083 ≈ 7

Estimate the sum.

7 + 6 = 13

3 0
3 years ago
Read 2 more answers
1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?
prisoha [69]

Answer:

For this question, the options are written the wrong way. In each of the answers below, the correct form of the question will be added.  

The answers are:

1. e) 4/9

2. a) 1/16

3. 980 girls

4. c) 2/3

5. d) 1/13

6. a) 42 boys

7. d) 1/21

8. b) 1/6

Step-by-step explanation:

1. What is the probability of getting a number greater than 2 on two rolls of a six-sided die both times?

a) 4/3

b) 2/6

c) 4/6

d) 3/6

e) 4/9

The correct answer is e) 4/9 because the probability of getting a number greater than 2 in two rolls is 4/6 * 4/6 =16/36 = 4/9

2. A fair coin is tossed four times. What is the probability that it will be heads every time?

a) 1/16

b) 4/2

c) 2

d) 4/16

e) 1

The correct answer is a) 1/16 because the probability of each time that the coin is tossed is 1/2, and for 4 tosses is 1/2*1/2*1/2*1/2 = 1/16

3. The ratio of the number of girls to the number of boys was 2 to 5. If 2,450 students were present, how many were girls and how many were boys?

The correct answer is 980 girls, because 2450*2/5 = 980

4. A die is rolled twice. What is the probability of rolling a 5 or getting an even number?

a) 3/1

b) 1/12

c) 2/3

d) 1/3

If the die is rolled twice there are 12 possible outcomes and 8 of those outcomes can be 5 or an even number. The probability is 8/12 = 2/3

5. If one card is drawn from a standard deck, what is the probability of getting a jack?

a) 4/13

b) 1/52

c) 52

d) 1/13

e) 4

In a standard deck, there are 13 jack cards, the probability of getting a jack the first time is 1/13

6. There are 210 boys trying out for football. If 20% made the team, how many were chosen?

a) 42

b) 10

c) 4200

d) 105

e) 20

The number of boys that will be picked for the team is 210*20% = 42

7. From 42 boys who made the team, one will be chosen as kicker and one will be chosen as quarterback. What is the probability of being chosen as the kicker or the quarterback?

a) 2/21

b) 1/42

c) 2

d) 1/21

e) 42

The probability of getting picked for one of the 2 positions is 2/42 = 1/21

8. Two dice are rolled. There are 36 possible outcomes of rolling two dice. What is the probability of getting a total of seven on one roll?

a) 7

b) 1/6

c) 0

d) 7/36

e) 1/36

There are 6 ways of getting a sum of 7 tossing 2 dice, 1+6, 6+1, 2+5, 5+2, 3+4, 4+3. The probability is 6/36 = 1/6

3 0
3 years ago
Ed is doing a survey of popular colors for cars for a school report. He decides to take a sample by sitting near a busy intersec
Goryan [66]
17+25=42
21+9=30

12 more white and blue than silver and red
3 0
3 years ago
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