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AlexFokin [52]
3 years ago
6

I need to find the unknown dimension of a rectangle if its area is 216 square miles and one dimension measures 6 miles

Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

36 miles

Step-by-step explanation:

The area of a rectangle = Length × Width

One dimension = 6 miles

Area = 216 square miles

Hence, the other dimension = 216 square miles/6 miles

= 36 miles

The unknown dimensions is 36 miles

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3/-3 = -1 I got this by dividing 3 by 3, but since it is -3 that means your answer will be negative. your answer is -1.

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sally is on a scavenger hunt. a clue tells her to walk 100 steps due south from the starting point and then walk west when she g
Sophie [7]

Answer:

She should take 112 steps west  

Step-by-step explanation:

* Lets explain the relation between the four directions

- North and South on the same line by in opposite directions

- East and West on the same line by in opposite directions

- East and West are perpendicular to the North and South

* Now lets study the situation i the problem

- Sally 100 steps due to South from the starting point

- Then she walk West when she gets the next clue

- The distance between her starting point and ending point is 150 steps

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- Lets consider her trip is a right angle triangle ABC, where AB

 her steps South and BC her steps West and AC the distance

 between her starting point and ending point

∵ AB = 100

∵ AC = 150

∵ m∠B = 90°

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∵ BC = √(AC² - AB²)

∴ BC = √(150² - 100²) = 50√5 = 111.8 steps

* She should take 112 steps west  

8 0
3 years ago
there is 3/5 of pie left if 4 friends wanted to share the pie equally how much pie would each friend receive/7095668/7abc4acb?ut
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when four coins are tossed simultaneously then what is the probability of getting two heads and two tails​
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3 years ago
Anybody who knows Pre Calc?? My last offer here<br> Solution PLS!
4vir4ik [10]

Answers:

  • true speed = 26.935546 knots
  • true bearing = 102.265139 degrees

The values are approximate. Round them however you need to.

====================================================

Explanation:

The diagram you have drawn is correct if you're only considering one current. Specifically current #1 which has the bearing of 290 degrees moving at 25 knots.

The red angle is 290 degrees. The remaining portion that is needed to get a full 360 degrees is 360-290 = 70. This adds to the blue portion in quadrant 1, which is 90, and we get 70+90 = 160. So the blue angle is 160 degrees.

The vector for current #1 is <25*cos(160), 25*sin(160)>

This approximates to <-23.4923155, 8.5505036>

All of this is for current #1.

------------

Vector #2 is much more simple in terms that there aren't messy decimal approximations here. The direction is due north, which means that the vector is pointing straight up toward 90 degrees.

We can then say: <12*cos(90), 12*sin(90)> = <12*0, 12*1> = <0, 12>

Vector #2 is <0,12>

When you wrote <12,0>, you were on the right track, but you had the coordinates swapped in the wrong order.

----------

Then we have to account for a wind going 4 knots in the southwest direction. This is at the angle 225 degrees (we rotate 180 degrees plus another 45 to get 225). So,

vector #3 = <4*cos(225), 4*sin(225)> = <-2.8284271, -2.8284271>

This vector's coordinates are approximate

---------

To recap everything so far, vectors 1 through 3 are the following

  • p = <-23.4923155, 8.5505036>
  • q = <0, 12>
  • r = <-2.8284271, -2.8284271>

I'm using variables to represent the vectors at this point, so we can then add them up to get...

s = p+q+r

s = <-23.4923155, 8.5505036> + <0,12> + <-2.8284271, -2.8284271>

s = <-23.4923155+0+(-2.8284271), 8.5505036+0+(-2.8284271)>

s = <-26.3207426, 5.7220765>

Vector s represents the sum of the three vectors p, q, and r. The two currents and the wind ultimately combine together to push the boat in the direction and along the length of vector s.

----------------------

Now that we know the coordinates of vector s, we use them to find the true speed and true bearing of the boat.

speed = sqrt(a^2 + b^2)

speed = sqrt( (-26.3207426)^2 + (5.7220765)^2 )

speed = 26.935546 knots, which is approximate

angle = arctan(b/a)

angle = arctan(5.7220765/(-26.3207426))

angle = -12.265139

Add 360 to this angle to find that we get to the coterminal angle of -12.265139+360 = 347.734861 degrees

This angle is in quadrant 4, which is the southeast quadrant. If we rotate another 360-347.734861 = 12.265139 degrees, going counterclockwise, then we'll face directly east. Then another 90 degree counterclockwise rotation has us face directly north.

In total, the true bearing is approximately 90+12.265139 = 102.265139 degrees

So we'll start aiming north, and then rotate roughly 102.265139 degrees toward the east to get to the true bearing.

4 0
3 years ago
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