Answer:
And on this case if we see the significance level given 
we see that 
so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.
Step-by-step explanation:
A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.
represent the p value for the test
O= obserbed values
E= expected values
The system of hypothesis for this case are:
Null hypothesis: ![O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i](https://tex.z-dn.net/?f=O_i%20%3D%20E_i%5B%2Ftex%5B%3C%2Fp%3E%3Cp%3EAlternative%20hypothesis%3A%20%5Btex%5DO_i%20%5Cneq%20E_i%20)
The statistic to check the hypothesis is given by:
On this case after calculate the statistic they got: 
And in order to calculate the p value we need to find first the degrees of freedom given by:
, where k represent the number of levels (on this cas we have 10 categories)
And in order to calculate the p value we need to calculate the following probability:
And on this case if we see the significance level given we see that so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.
Answer: true
Step-by-step explanation:
Answer:
15 m
Step-by-step explanation:
First split the shape into a square and a triangle, then find the area of the square by multipliyng the sides to get.
Next find the length of the traignel by subtracting 3 from 9 to get for then find the area of the triangle by multiplying 4 by 3 to get 12 then divide by 2 to get the area which is 6.
Finally add the 9 to the 6 to get 15
3 * 3 = 9
9 - 3 = 4
4 * 3 = 12/2 = 6
6+9=15
The original number to the nearest tenth is 23.8
Answer: 0.5143
Step-by-step explanation:
Probability of students who are over 21 years old = 30% = 0.3
Probability of students who are under 21 years old = 100% - 30% = 70% = 0.7
Probability of drinking alcohol for over 21 = 80% = 0.8
Probability of not drinking alcohol for over 21 = 100%- 80% = 20% = 0.2
Let the probability of the students who are not over 21, that drink alcohol be p.
Total probability of a college student drinking alcohol = (0.3 × 0.8) + (0.7 × p)
0.6 = (0.3 × 0.8) + (0.7 × p)
0.6 = 0.24 + 0.7p
0.7p = 0.6 - 0.24
0.7p = 0.36
p = 0.36/0.7
p = 0.5143
The probability of the students who are not over 21, that drink alcohol is 0.5143.
