(a) We have ⌊<em>x</em>⌋ = 5 if 5 ≤ <em>x</em> < 6, and similarly ⌊<em>x</em>/3⌋ = 5 if
5 ≤ <em>x</em>/3 < 6 ==> 15 ≤ <em>x</em> < 18
(b) ⌊<em>x</em>⌋ = -2 if -2 ≤ <em>x</em> < -1, so ⌊<em>x</em>/3⌋ = -2 if
-2 ≤ <em>x</em>/3 < -1 ==> -6 ≤ <em>x</em> < -3
In general, ⌊<em>x</em>⌋ = <em>n</em> if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
Answer:
(5 , 7)
Step-by-step explanation:
let a = the number of adult tickets
let c = the number of children tickets
then we have to solve the following system
a + c = 12
14.5a + 9c = 135.5
we proceed by Substitution:
c = 12 - a
14.5a + 9c = 135.5
After some calculations we find
a=5 and c=7
It’s -63 all you would be multiple like normal 63 which then you put a negative symbol on front
This stuff is way to hard
