A circle has its center in Quadrant I. It is tangent to the y-axis at (0,2) and its radius is 3. What is the equation of the cir
cle? Explain the process you use to find the equation.
1 answer:
We know that
the equation of a circle is
(x-h)²+(y-k)²=r²
r=3 units
where the center is the point (h,k)
if the circle is tangent to the y-axis at (0,2) and <span> its center in Quadrant I
</span><span>then
the center is the point (0+3,2)--------> (3,2)
therefore
the answer is
</span>(x-3)²+(y-2)²=9
see the attached figure
the equation of a circle is
(x-h)²+(y-k)²=r²
r=3 units
where the center is the point (h,k)
if the circle is tangent to the y-axis at (0,2) and <span> its center in Quadrant I
</span><span>then
the center is the point (0+3,2)--------> (3,2)
therefore
the answer is
</span>(x-3)²+(y-2)²=9
see the attached figure
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Answer:
401
Step-by-step explanation:
1. Approach
To solve this problem, one first has to think about the given figure in a certain way. In the figure, one can see that it is a circle attached on either side of a rectangle. To find the perimeter of the figure, one has to find the circumference of the circle and then add two sides of the rectangle to the answer
2. Circumference of the circle
The formula to find the circumference of a circle is;
(pi) or
(pi)
~ diameter times the value (pi)
Normally to find the circumference of a semicircle, one would have to divide this formula by 2, but since in this case, one has to add two congruent semicircles, so therefore, the effect of dividing the equation by two, only to multiply by two again cancels, and hence, there is no need to divide by 2.
Substitute in the values;
(78)(pi)
~ 245
3. Find the perimeter of the entire object
Now, one has to add the two additional sides of the figure, to the circumferences of the semicircles to get the final answer;
78 + 78 + 245
= 401