Answer:
1. 0.00352 M
2. 2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)
3. 0.00534 M
Explanation:
1.
Mass of strontium hydroxide= 10.45 g
Volume of solution = 41.00 ml
Number of moles = mass of Sr(OH)2/molar mass of Sr(OH)2 = 10.45g/121.63 g/mol= 0.0859 moles
Molarity= number of moles × volume = 0.0859 ×41/1000 = 0.00352 M
2.
2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)
3.
Concentration of acid CA= the unknown
Volume of acid VA= 31.5 ml
Concentration of base CB= 0.00352 M
Volume of base VB= 23.9 ml
Number of moles of acid NA= 2
Number of moles of base NB= 1
From;
CAVA/CBVB = NA/NB
CAVANB= CBVBNA
CA= CBVBNA/VANB
CA= 0.00352 × 23.9 ×2/31.5 ×1
CA= 0.00534 M
<span>It is known that amu is equal to the molar mass of 1 mole of substance. Therefore,
</span>
Weight of one mole of uranium = 238 g/mol
The molar mass or molecular weight for U205 is 556 g/mol.
(238 x 2) + (16 x 5) = 556 g/mol
Answer:
5.5 moles of sodium are produced
Explanation:
Given data:
Number of moles of hydrogen = 2.75 mol
Number of moles of Na produced = ?
Solution:
Chemical equation:
H₂ + 2NaCl → 2HCl + 2Na
Now we will compare the moles of hydrogen and sodium from balance chemical equation:
H₂ : Na
1 : 2
2.75 : 2/1×2.75 = 5.5 mol
Thus, 5.5 moles of sodium are produced.
Answer: the answer is B!
Explanation:
S and p’s are valence electrons and if added, there is 7 in total !
I think Alcohol would be the correct answer, but i'm not too sure since my mind is fuzzy about chemistry
