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statuscvo [17]
3 years ago
14

The image represents a typical temperate forest food web. Use the image to answer the following questions(s).

Chemistry
2 answers:
Karolina [17]3 years ago
4 0

Answer:

D

Explanation:

Nikolay [14]3 years ago
3 0

Answer:

Answer is D

Explanation:

secondary consumers eat meat and manly eat the primary consumers

BRAINILEST PLEASE

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What is the approximate total number of atoms in 1.0 mole of lithium?
chubhunter [2.5K]

Answer:

6.0 x 10 to the power of 23

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3 years ago
How many electrons are in ewch energy levels
joja [24]

Answer:

To determine how many electrons fit in each energy level, use the formula:

2n²

N is equal to the number of energy levels. Using this formula, we can determine that there are:

  • First energy level holds 2 electrons
  • Second energy level holds 8 electrons
  • Third energy level holds 18 electrons
  • Fourth energy level holds 32 electrons
  • And so on...

Keep in mind though, that for an atom's outermost shell, it can only contain 8 valence electrons due to the octet rule that states that an element only needs eight electrons in their outermost shell in order to be stable.

8 0
3 years ago
If the temperature of the earth's layers increases by about 90 degrees fahrenheit for every 1 mile from the surface and you are
bogdanovich [222]
The rate of change of the temperature of the Earth's surface is given to,
                                       90°F/mile
To determine the temperature x miles away from the surface, we multiply the depth by the given rate. This will give us the answer of,
                                  T = (90°F/mile)(90 mile)
                                      = 8100°F
Thus, the temperature 90 miles deep in the Earth's surface is equal to 8100°F. 
4 0
3 years ago
Read 2 more answers
What is the electric force on a proton 2.5 fmfm from the surface of the nucleus? Hint: Treat the spherical nucleus as a point ch
sammy [17]

Explanation:

It is known that charge on xenon nucleus is q_{1} equal to +54e. And, charge on the proton is q_{2} equal to +e. So, radius of the nucleus is as follows.

            r = \frac{6.0}{2}

              = 3.0 fm

Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.

              d = r + 2.5

                 = (3.0 + 2.5) fm

                 = 5.5 fm

                 = 5.5 \times 10^{-15} m     (as 1 fm = 10^{-15})

Therefore, electrostatic repulsive force on proton is calculated as follows.

              F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

Putting the given values into the above formula as follows.

           F = \frac{1}{4 \pi \epsilon_{o}} \frac{q_{1}q_{2}}{d^{2}}

              = (9 \times 10^{9}) \frac{54e \times e}{(5.5 \times 10^{-15})^{2}}

              = (9 \times 10^{9}) \frac{54 \times (1.6 \times 10^{-19})^{2}}{(5.5 \times 10^{-15})^{2}}

              = 411.2 N

or,           = 4.1 \times 10^{2} N

Thus, we ca conclude that 4.1 \times 10^{2} N is the electric force on a proton 2.5 fm from the surface of the nucleus.

8 0
4 years ago
CAN SOMEONE PLEASE HELP ME WITH THIS
klio [65]

me too please l need to know how to use this

6 0
2 years ago
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