Answer: approximately 4.74pKa is when you take the -log10 of your Ka. Therefore, taking the -log10(1.8*10-5), we get a value of approximately 4.74 for our pKa for acetic acid.
Explanation: hope this helps
The atoms will form intermolecular bonds and solidify
Moles of oxygen = mass/molar mass of O2 = 8/31.998 = 0.25 moles.
Number of particles = moles x 6.02 x 10^23 = 0.25 x 6.02 x 10^23 = 1.505 x 10^23 particles.
Hope this helps!
Answer : The value of 
across the membrane is 6.80 kJ/mol
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = ?
R = gas constant = 8.314 J/K.mol
T = temperature = 
= equilibrium constant
= concentration inside the cell = 
= concentration outside the cell = 
Now put all the given values in the above formula, we get:
Thus, the value of across the membrane is 6.80 kJ/mol
Answer:
All chemical equations goes to the law of conservation of mass which says that matter can not be destroyed nor created which means there has to be an equal amount of atoms of each element on both sides of the equation. I hope that helps, I'm learning this as well.
