Question

What is the molarity of the solution produced when 85.6 g of hydrochloric acid (HCl) is dissolved in enough water to prepare 385 mL of solution?

Answer 1

Answer:

6.09 M

Explanation:

M(HCl) = 1 +35.5 = 36.5 g/mol

85.6 g * 1 mol/36.5 g = 2.3452 mol HCl

Molarity = mol solute/ L solution = 2.3452 mol/0.385 L = 6.09 mol/L =6.09 M